Polar Coordinates — Question 6

Section 10-6 · Calculus pages 1831–1832

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Question 6

Problem

Sketch mentally r=1−2cos⁡θr=1-2\cos\theta. Why does it have an inner loop?

Diagram shown in the original SVG worksheet.

Question 6 – Solution

Diagram shown in the original SVG worksheet.

Solution

  1. Use the polar–Cartesian relationships x=rcos⁡θ,y=rsin⁡θ,r2=x2+y2.x=r\cos\theta,\qquad y=r\sin\theta,\qquad r^2=x^2+y^2. Equivalent polar coordinates satisfy (r,θ)=(r,θ+2kπ)=(−r,θ+(2k+1)π).(r,\theta)=(r,\theta+2k\pi)=(-r,\theta+(2k+1)\pi).

  2. Apply the identity that matches the requested conversion, symmetry test, or intersection, and then check the resulting point or curve in the original polar equation.

  3. The radius becomes negative when cos⁡θ>1/2\cos\theta>1/2, i.e. near θ=0\theta=0.

  4. Negative radii plot in the opposite direction, producing the inner loop.