Arc Length with Polar Coordinates — Question 5

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Question 5

Problem

A circle of the same radius is r=2Rcos⁡θr=2R\cos\theta. Which interval traces it once, and what length results?

See the diagram in the original worksheet below.

Original worksheet page 1: question and worked solution for 3-9-005
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Question 5 – Solution

See the diagram in the original worksheet below.

Solution

  1. Differentiate the polar radius to obtain r′=dr/dθr'=dr/d\theta and choose an interval that traces the requested arc exactly once.

  2. Use the polar arc-length formula L=∫abr2+(drdθ)2dθ.L=\int_a^b\sqrt{r^2+\left(\frac{dr}{d\theta}\right)^2}\,d\theta. Simplify the expression under the square root before evaluating or reporting the integral.

  3. −π/2≤θ≤π/2-\pi/2\le\theta\le\pi/2 traces it once.

  4. The speed simplifies to 2R2R, so L=2Rπ=2πR.L=2R\pi=\boxed{2\pi R}.

Original worksheet page 2: question and worked solution for 3-9-005

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