Polar Coordinates — Question 6

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Question 6

Problem

Sketch mentally r=1−2cos⁡θr=1-2\cos\theta. Why does it have an inner loop?

See the diagram in the original worksheet below.

Original worksheet page 1: question and worked solution for 3-6-006
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Question 6 – Solution

See the diagram in the original worksheet below.

Solution

  1. Use the polar–Cartesian relationships x=rcos⁡θ,y=rsin⁡θ,r2=x2+y2.x=r\cos\theta,\qquad y=r\sin\theta,\qquad r^2=x^2+y^2. Equivalent polar coordinates satisfy (r,θ)=(r,θ+2kπ)=(−r,θ+(2k+1)π).(r,\theta)=(r,\theta+2k\pi)=(-r,\theta+(2k+1)\pi).

  2. Apply the identity that matches the requested conversion, symmetry test, or intersection, and then check the resulting point or curve in the original polar equation.

  3. The radius becomes negative when cos⁡θ>1/2\cos\theta>1/2, i.e. near θ=0\theta=0.

  4. Negative radii plot in the opposite direction, producing the inner loop.

Original worksheet page 2: question and worked solution for 3-6-006

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