Limits at Infinity, Part I — Question 10

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Question 10

Evaluate the limit: limx→∞5x2+3x−72x2−x+4\lim_{x \to \infty} \frac{5x^2 + 3x - 7}{2x^2 - x + 4}

Original worksheet page 1: question and worked solution for 2-7-010
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Question 10 - Solution

We are given: limx→∞5x2+3x−72x2−x+4\lim_{x \to \infty} \frac{5x^2 + 3x - 7}{2x^2 - x + 4}

Step 1: Factor out the highest power of xx (which is x2x^2) from both the numerator and denominator:

=limx→∞x2(5+3x−7x2)x2(2−1x+4x2)= \lim_{x \to \infty} \frac{x^2\left(5 + \frac{3}{x} - \frac{7}{x^2} \right)}{x^2\left(2 - \frac{1}{x} + \frac{4}{x^2} \right)}

Step 2: Cancel the common factor x2x^2:

=limx→∞5+3x−7x22−1x+4x2= \lim_{x \to \infty} \frac{5 + \frac{3}{x} - \frac{7}{x^2}}{2 - \frac{1}{x} + \frac{4}{x^2}}

Step 3: Take the limit as x→∞x \to \infty. Terms with 1xn→0\frac{1}{x^n} \to 0:

=5+0−02−0+0=52= \frac{5 + 0 - 0}{2 - 0 + 0} = \boxed{\frac{5}{2}}

Original worksheet page 2: question and worked solution for 2-7-010

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