Logarithm Functions — Question 6

Question 6 - Solution

(a) Compute the magnitude $R$: $$R = \log_{10} \left( \frac{10^{-1.5}}{10^{-4}} \right) = \log_{10}(10^{2.5}) = \boxed{2.5}$$

(b) Find the intensity for $R = 6.2$: $$R = \log_{10} \left( \frac{I}{10^{-4}} \right) \Rightarrow 10^R = \frac{I}{10^{-4}} \Rightarrow I = 10^R \cdot 10^{-4}$$ $$I = 10^{6.2 - 4} = 10^{2.2} \approx \boxed{158.49}$$

(c) Compare intensities of magnitudes 7.2 and 5.2:

Let $I_1$ and $I_2$ be the intensities corresponding to magnitudes 7.2 and 5.2, respectively.

$$\log_{10} \left( \frac{I_1}{I_0} \right) = 7.2 \Rightarrow I_1 = 10^{7.2} \cdot I_0,\quad \log_{10} \left( \frac{I_2}{I_0} \right) = 5.2 \Rightarrow I_2 = 10^{5.2} \cdot I_0$$

$$\frac{I_1}{I_2} = \frac{10^{7.2} \cdot I_0}{10^{5.2} \cdot I_0} = 10^{7.2 - 5.2} = 10^2 = \boxed{100}$$

So the magnitude 7.2 earthquake is 100 times more intense than the 5.2 earthquake.