Solving Trig Equations with Calculators, Part II — Question 8

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Question 8

Solve the equation 2cos⁡(2x)−1=0.62\cos(2x) - 1 = 0.6 for all x∈[0,2π]x \in [0, 2\pi], and round your answers to two decimal places.

Original worksheet page 1: question and worked solution for 1-6-008
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Question 8 - Solution

Step 1: Isolate the trigonometric function. The equation becomes

cos⁡(2x)=0.8,u=2x,0≤u≤4π.\cos(2x)=0.8,\qquad u=2x,\qquad 0\le u\le 4\pi.

Let α=arccos⁡(0.8)\alpha=\arccos(0.8). All solutions are

u=±α+2kπ,k∈ℤ.u=\pm\alpha+2k\pi,\qquad k\in\mathbb Z.

Step 2: Restrict and convert. Keep precisely the values of uu in [0,4π][0,4\pi] and divide by 22.

Evaluating the inverse function at full precision and rounding only the final values gives

x≈0.32,2.82,3.46,5.96.\boxed{x\approx 0.32,\ 2.82,\ 3.46,\ 5.96}.

These are all 4 solutions in the stated interval, in radians. Substitution of the unrounded values verifies the original equation.

Original worksheet page 2: question and worked solution for 1-6-008

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