Solving Trig Equations with Calculators, Part II — Question 2

Question 2 - Solution

Step 1: Isolate the trigonometric function. The equation becomes

$$\sin(2x)=0.6,\qquad u=2x,\qquad 0\le u\le 4\pi.$$

Let $\alpha=\arcsin(0.6)$. All solutions are

$$u=\alpha+2k\pi\quad\text{or}\quad u=\pi-\alpha+2k\pi,\qquad k\in\mathbb Z.$$

Step 2: Restrict and convert. Keep precisely the values of $u$ in $[0,4\pi]$ and divide by $2$.

Evaluating the inverse function at full precision and rounding only the final values gives

$$\boxed{x\approx 0.32,\ 1.25,\ 3.46,\ 4.39}.$$

These are all 4 solutions in the stated interval, in radians. Substitution of the unrounded values verifies the original equation.