Momentum and Kinetic Energy in Collisions — Question 10

Section 9-7 · Physics pages 1290–1291

Question 10 Uncertainty may prevent a confident elastic label An isolated two-body experiment bounds the initial kinetic energy by [19.8, 20.2] J and the final by [19.6, 20.0] J. Treat the intervals as independent hard bounds. loss (J) −0.2 0 0.6 The allowed energy-change interval crosses the elastic value. (a) Find the full interval for Ki −Kf. (b) Can the measurements prove an inelastic collision, or are elastic and superelastic outcomes still compatible?
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Question 10 - Solution Uncertainty may prevent a confident elastic label loss (J) −0.2 0 0.6 (a) Derivation and calculation For independent bounded intervals, the smallest and largest losses use opposite endpoints: Lmin = 19.8 −20.0 = −0.2 J, Lmax = 20.2 −19.6 = 0.6 J. L = Ki −Kf ∈[−0.2, 0.6] J . (b) Result and interpretation The interval contains each sign: L > 0 : inelastic, L = 0 : elastic, L < 0 : superelastic. None of these classifications can be excluded by the supplied uncertainty bounds. Physical check A positive difference of central values is not sufficient to establish a strictly positive loss.

Question 10

Uncertainty may prevent a confident elastic label

An isolated two-body experiment bounds the initial kinetic energy by [19.8,20.2]J[19.8,20.2]\,\mathrm J and the final by [19.6,20.0]J[19.6,20.0]\,\mathrm J. Treat the intervals as independent hard bounds.

Diagram shown in the original SVG worksheet.

  1. Find the full interval for Ki−KfK_i-K_f.

  2. Can the measurements prove an inelastic collision, or are elastic and superelastic outcomes still compatible?

Question 10 - Solution

Uncertainty may prevent a confident elastic label

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

For independent bounded intervals, the smallest and largest losses use opposite endpoints: Lmin=19.8−20.0=−0.2J,Lmax=20.2−19.6=0.6J.L_{\min}=19.8-20.0=-0.2\ \mathrm J,\qquad L_{\max}=20.2-19.6=0.6\ \mathrm J. L=Ki−Kf∈[−0.2,0.6]J.\boxed{L=K_i-K_f\in[-0.2,0.6]\ \mathrm J}.

(b) Result and interpretation

The interval contains each sign: L>0: inelastic,L=0: elastic,L<0: superelastic.L>0:\text{ inelastic},\qquad L=0:\text{ elastic},\qquad L<0:\text{ superelastic}. None of these classifications can be excluded by the supplied uncertainty bounds.

Physical check

A positive difference of central values is not sufficient to establish a strictly positive loss.