Conservation of Energy — Question 1

Section 8-7 · Physics pages 1132–1133

Question 1 Mechanical energy converted during a spring excursion A 1 kg block attached to a horizontal ideal spring of k=100 N/m is released from rest at extension −0.30 m. It next stops at +0.10 m on a rough fixed surface. Include block, spring and surface in a thermally insulated system; no external agent does work. block −0.30 m to +0.10 m The signed extension changes through zero; friction acts over the whole excursion. (a) Find the mechanical-energy decrease and thermal-energy increase. (b) Find the displacement-averaged friction magnitude during the excursion. (c) If the maximum static friction is 10 N, can the block remain at this stop?
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Question 1 - Solution Mechanical energy converted during a spring excursion block −0.30 m to +0.10 m (a) Compare the two zero-speed configurations. Both endpoint speeds vanish, so the mechanical energies are purely elastic: Ei = 50(.30)2 = 4.5 J, Ef = 50(.10)2 = .5 J. ∆Emech = −4 J , ∆Eth = +4 J . (b) Use the full path length. Use the complete distance traveled between the stops: s = .10 −(−.30) = .40 m, f = ∆Eth/s = 4/.40 = 10 N . (c) Check static feasibility separately. The spring force at the final point is leftward: Fs = −kx = −100(.10) = −10 N. A rightward static force of 10 N is within the stated bound, |fs| ≤10 N. The block can remain at rest at the limiting value; energy conservation alone does not establish this force condition.

Question 1

Mechanical energy converted during a spring excursion

A 1 kg block attached to a horizontal ideal spring of k=100 N/m is released from rest at extension −0.30-0.30 m. It next stops at +0.10 m on a rough fixed surface. Include block, spring and surface in a thermally insulated system; no external agent does work.

Diagram shown in the original SVG worksheet.

  1. Find the mechanical-energy decrease and thermal-energy increase.

  2. Find the displacement-averaged friction magnitude during the excursion.

  3. If the maximum static friction is 10 N, can the block remain at this stop?

Question 1 - Solution

Mechanical energy converted during a spring excursion

Diagram shown in the original SVG worksheet.

(a) Compare the two zero-speed configurations.

Both endpoint speeds vanish, so the mechanical energies are purely elastic: Ei=50(.30)2=4.5J,Ef=50(.10)2=.5J.E_i=50(.30)^2=4.5\ \mathrm J,\qquad E_f=50(.10)^2=.5\ \mathrm J. ΔEmech=−4J,ΔEth=+4J.\boxed{\Delta E_{\mathrm{mech}}=-4\ \mathrm J},\qquad\boxed{\Delta E_{\mathrm{th}}=+4\ \mathrm J}.

(b) Use the full path length.

Use the complete distance traveled between the stops: s=.10−(−.30)=.40m,f¯=ΔEth/s=4/.40=10N.s=.10-(-.30)=.40\ \mathrm m,\qquad\boxed{\overline f=\Delta E_{\mathrm{th}}/s=4/.40=10\ \mathrm N}.

(c) Check static feasibility separately.

The spring force at the final point is leftward: Fs=−kx=−100(.10)=−10N.F_s=-kx=-100(.10)=-10\ \mathrm N. A rightward static force of 10 N is within the stated bound, |fs|≤10|f_s|\leq10 N. The block can remain at rest at the limiting value; energy conservation alone does not establish this force condition.