Work Done on a System by an External Force — Question 10

Section 8-6 · Physics pages 1130–1131

Question 10 The location of external energy delivery matters A particle starts with K=10 J and U=0. Along its route a smooth potential barrier reaches 12 J, then falls back to zero. A drive can add 5 J of work, either entirely before the barrier or only after it. There is no friction. route U 12 J early drive late drive The two possible drive locations lie on opposite sides of the potential barrier. (a) Can a drive located only after the barrier help the particle cross? (b) If all 5 J is added before climbing, find kinetic energy at the barrier top. (c) Explain why inserting an eventual +5 J into the initial energy balance can be causally wrong.
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Question 10 - Solution The location of external energy delivery matters route U 12 J early drive late drive (a) Examine the energy available before the drive. Before a downstream drive is reached, no work has yet been added: E = 10 J < Umax = 12 J. The particle reaches a turning point at U = 10 J and cannot access the drive beyond the barrier. (b) Place the transfer before it is needed. Early input raises the total before the climb: E+ = 10 + 5 = 15 J, Ktop = 15 −12 = 3 J . The energy stays above the barrier, so passage is possible. (c) Use cumulative external work up to each point. At each location the correct balance uses cumulative work: K(x) + U(x) = Ei + Wext(up to x). An eventual downstream transfer is not available at an earlier blocked point. Inserting it prematurely assumes the very passage that must be established.

Question 10

The location of external energy delivery matters

A particle starts with K=10 J and U=0. Along its route a smooth potential barrier reaches 12 J, then falls back to zero. A drive can add 5 J of work, either entirely before the barrier or only after it. There is no friction.

Diagram shown in the original SVG worksheet.

  1. Can a drive located only after the barrier help the particle cross?

  2. If all 5 J is added before climbing, find kinetic energy at the barrier top.

  3. Explain why inserting an eventual +5 J into the initial energy balance can be causally wrong.

Question 10 - Solution

The location of external energy delivery matters

Diagram shown in the original SVG worksheet.

(a) Examine the energy available before the drive.

Before a downstream drive is reached, no work has yet been added: E=10J<Umax=12J.E=10\ \mathrm J< U_{\max}=12\ \mathrm J. The particle reaches a turning point at U=10U=10 J and cannot access the drive beyond the barrier.

(b) Place the transfer before it is needed.

Early input raises the total before the climb: E+=10+5=15J,Ktop=15−12=3J.E_+=10+5=15\ \mathrm J,\qquad\boxed{K_{\mathrm{top}}=15-12=3\ \mathrm J}. The energy stays above the barrier, so passage is possible.

(c) Use cumulative external work up to each point.

At each location the correct balance uses cumulative work: K(x)+U(x)=Ei+Wext(up to x).K(x)+U(x)=E_i+W_{\mathrm{ext}}(\text{up to }x). An eventual downstream transfer is not available at an earlier blocked point. Inserting it prematurely assumes the very passage that must be established.