Work Done on a System by an External Force — Question 7

Section 8-6 · Physics pages 1124–1125

Question 7 Zero resultant force with nonzero external work Assume no heat transfer across the stated system boundary during the process unless otherwise specified. Two external agents pull outward on the ends of a deformable device with equal constant 10 N forces. The left end moves left 0.10 m and the right end moves right 0.10 m. Its total kinetic energy is unchanged between the initial and final configurations. device 10 N 10 N 0.10 m left 0.10 m right Equal opposite forces act at points that move apart. (a) Find the vector sum of external forces. (b) Find the total external work. (c) If the device warms by 0.50 J and no other energy store changes except elastic energy, find its elastic-energy increase.
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Question 7 - Solution Zero resultant force with nonzero external work device 10 N 10 N 0.10 m left 0.10 m right (a) Opposite equal forces cancel as vectors. Taking rightward as positive,⃗ Fext = (−10 + 10)ˆi = 0 . This constrains the resultant force, not the relative motion of the endpoints. (b) Sum force-displacement products at both ends. Each force acts along its own endpoint displacement: WL = (−10)(−.10) = 1 J, WR = (10)(.10) = 1 J. Wext = WL + WR = 2 J . (c) Account for deformation and heating. The endpoint kinetic energies are equal: 2 = ∆K + ∆Uelastic + ∆Eth = 0 + ∆Uelastic + .50. ∆Uelastic = 1.50 J . Zero resultant force does not imply zero work on a deformable system.

Question 7

Zero resultant force with nonzero external work

Assume no heat transfer across the stated system boundary during the process unless otherwise specified. Two external agents pull outward on the ends of a deformable device with equal constant 10 N forces. The left end moves left 0.10 m and the right end moves right 0.10 m. Its total kinetic energy is unchanged between the initial and final configurations.

Diagram shown in the original SVG worksheet.

  1. Find the vector sum of external forces.

  2. Find the total external work.

  3. If the device warms by 0.50 J and no other energy store changes except elastic energy, find its elastic-energy increase.

Question 7 - Solution

Zero resultant force with nonzero external work

Diagram shown in the original SVG worksheet.

(a) Opposite equal forces cancel as vectors.

Taking rightward as positive, F→ext=(−10+10)î=0.\boxed{\vec F_{\mathrm{ext}}=(-10+10)\hat i=0}. This constrains the resultant force, not the relative motion of the endpoints.

(b) Sum force-displacement products at both ends.

Each force acts along its own endpoint displacement: WL=(−10)(−.10)=1J,WR=(10)(.10)=1J.W_L=(-10)(-.10)=1\ \mathrm J,\qquad W_R=(10)(.10)=1\ \mathrm J. Wext=WL+WR=2J.\boxed{W_{\mathrm{ext}}=W_L+W_R=2\ \mathrm J}.

(c) Account for deformation and heating.

The endpoint kinetic energies are equal: 2=ΔK+ΔUelastic+ΔEth=0+ΔUelastic+.50.2=\Delta K+\Delta U_{\mathrm{elastic}}+\Delta E_{\mathrm{th}}=0+\Delta U_{\mathrm{elastic}}+.50. ΔUelastic=1.50J.\boxed{\Delta U_{\mathrm{elastic}}=1.50\ \mathrm J}. Zero resultant force does not imply zero work on a deformable system.