Work Done on a System by an External Force — Question 5

Section 8-6 · Physics pages 1120–1121

Question 5 Two boundaries for one sliding-and-stopping event Assume no heat transfer across the stated system boundary during the process unless otherwise specified. A 1 kg puck slides at 4 m/s across a fixed rough horizontal plate and stops after 2 m. No other horizontal force acts. Neglect plate recoil. 4 m/s A larger system includes both the puck and plate; the thermal partition is unspecified. (a) Find friction work on the puck and its average magnitude. (b) For puck plus plate, find external horizontal work and thermal-energy increase. (c) Can the data determine how much of the thermal increase belongs to the puck alone?
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Question 5 - Solution Two boundaries for one sliding-and-stopping event 4 m/s (a) Use the puck kinetic-energy loss. For the puck alone, Wf = Kf −Ki = 0 −1 2(1)(4)2 = −8 J , f = |Wf|/s = 8/2 = 4 N . (b) Move the rubbing interaction inside the boundary. For puck plus plate, rubbing lies inside the boundary: Wext,h = 0 , 0 = ∆K + ∆Eth = −8 + ∆Eth. Thus ∆Eth = 8 J . (c) Do not infer an unmeasured partition. The measurements fix only the sum: ∆Eth,puck + ∆Eth,plate = 8 J. Material properties and contact behavior determine the partition. The puck’s 8 J kinetic loss is not necessarily its own thermal gain.

Question 5

Two boundaries for one sliding-and-stopping event

Assume no heat transfer across the stated system boundary during the process unless otherwise specified. A 1 kg puck slides at 4 m/s across a fixed rough horizontal plate and stops after 2 m. No other horizontal force acts. Neglect plate recoil.

Diagram shown in the original SVG worksheet.

  1. Find friction work on the puck and its average magnitude.

  2. For puck plus plate, find external horizontal work and thermal-energy increase.

  3. Can the data determine how much of the thermal increase belongs to the puck alone?

Question 5 - Solution

Two boundaries for one sliding-and-stopping event

Diagram shown in the original SVG worksheet.

(a) Use the puck kinetic-energy loss.

For the puck alone, Wf=Kf−Ki=0−12(1)(4)2=−8J,\boxed{W_f=K_f-K_i=0-\tfrac12(1)(4)^2=-8\ \mathrm J}, f¯=|Wf|/s=8/2=4N.\boxed{\overline f=|W_f|/s=8/2=4\ \mathrm N}.

(b) Move the rubbing interaction inside the boundary.

For puck plus plate, rubbing lies inside the boundary: Wext,h=0,0=ΔK+ΔEth=−8+ΔEth.\boxed{W_{\mathrm{ext,h}}=0},\qquad0=\Delta K+\Delta E_{\mathrm{th}}=-8+\Delta E_{\mathrm{th}}. Thus ΔEth=8J\boxed{\Delta E_{\mathrm{th}}=8\ \mathrm J}.

(c) Do not infer an unmeasured partition.

The measurements fix only the sum: ΔEth,puck+ΔEth,plate=8J.\Delta E_{{\mathrm{th}},puck}+\Delta E_{{\mathrm{th}},plate}=8\ \mathrm J. Material properties and contact behavior determine the partition. The puck’s 8 J kinetic loss is not necessarily its own thermal gain.