Conservation of Mechanical Energy — Question 10

Section 8-4 · Physics pages 1090–1091

Question 10 Energy fractions depend on the stated potential zero A system with conserved mechanical energy has K=6 J and U=4 J in one convention. A second convention adds 10 J to U at every configuration. reference 1 U = 4, E = 10 J reference 2 U = 14, E = 20 J The same 6 J kinetic energy remains after shifting both potential and total energy. (a) Find E and the fraction K/E in each convention. (b) Does changing the convention alter any speeds or turning positions? (c) How should a claim such as half the energy is kinetic be made unambiguous?
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Question 10 - Solution Energy fractions depend on the stated potential zero reference 1 U = 4, E = 10 J reference 2 U = 14, E = 20 J (a) Shift the total with the potential. In the first convention, E = 6 + 4 = 10 J, K/E = .60 . After shifting U by 10 J, eE = 6 + 14 = 20 J, K/ eE = .30 . (b) Check the invariant difference. The measurable energy gap is invariant: eE −eU = (E + 10) −(U + 10) = E −U = K. Speeds and turning positions E = U therefore do not change. (c) Specify the reference and the energy being compared. An absolute energy fraction depends on the datum: K E + C̸ = K E in general. Specify the potential zero and the total being compared, or use a defined available-energy difference, whose value is invariant under a common shift.

Question 10

Energy fractions depend on the stated potential zero

A system with conserved mechanical energy has K=6 J and U=4 J in one convention. A second convention adds 10 J to U at every configuration.

Diagram shown in the original SVG worksheet.

  1. Find E and the fraction K/E in each convention.

  2. Does changing the convention alter any speeds or turning positions?

  3. How should a claim such as half the energy is kinetic be made unambiguous?

Question 10 - Solution

Energy fractions depend on the stated potential zero

Diagram shown in the original SVG worksheet.

(a) Shift the total with the potential.

In the first convention, E=6+4=10J,K/E=.60.\boxed{E=6+4=10\ \mathrm J,\qquad K/E=.60}. After shifting UU by 10 J, Ẽ=6+14=20J,K/Ẽ=.30.\boxed{\widetilde E=6+14=20\ \mathrm J,\qquad K/\widetilde E=.30}.

(b) Check the invariant difference.

The measurable energy gap is invariant: Ẽ−Ũ=(E+10)−(U+10)=E−U=K.\widetilde E-\widetilde U=(E+10)-(U+10)=E-U=K. Speeds and turning positions E=UE=U therefore do not change.

(c) Specify the reference and the energy being compared.

An absolute energy fraction depends on the datum: KE+C≠KEin general.\frac K{E+C}\ne\frac KE\quad\text{in general}. Specify the potential zero and the total being compared, or use a defined available-energy difference, whose value is invariant under a common shift.