Determining Potential Energy Values — Question 8

Section 8-3 · Physics pages 1066–1067

Question 8 When an infinite reference is unavailable An idealized force is Fy = −5 N at every positive height y, extending indefinitely. Someone proposes defining U=0 at y approaching infinity. H U(H) −U(0) The finite-reference potential difference grows without bound in this idealized model. (a) Find U(H)-U(0) for a finite height H. (b) Does this difference approach a finite limit as H grows? (c) Give a valid finite reference and the work from y=2 to y=5 m.
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Question 8 - Solution When an infinite reference is unavailable H U(H) −U(0) (a) Integrate over a finite interval first. For finite H, integrate before taking any limit: U(H) −U(0) = − ∫H 0 (−5)dy = 5H J (H in m). (b) Test the proposed limiting assignment. The proposed reference fails because lim H→∞[U(H) −U(0)] = lim H→∞5H = +∞. No finite constant yields finite potential at finite height and zero at infinity for this constant-force model. (c) Choose a permissible datum. A valid finite reference is U(0) = 0: U(y) = 5y, W2→5 = U(2) −U(5) = 10 −25 = −15 J . Finite potential differences remain well defined.

Question 8

When an infinite reference is unavailable

An idealized force is Fy=−5F_y=-5 N at every positive height y, extending indefinitely. Someone proposes defining U=0 at y approaching infinity.

Diagram shown in the original SVG worksheet.

  1. Find U(H)-U(0) for a finite height H.

  2. Does this difference approach a finite limit as H grows?

  3. Give a valid finite reference and the work from y=2 to y=5 m.

Question 8 - Solution

When an infinite reference is unavailable

Diagram shown in the original SVG worksheet.

(a) Integrate over a finite interval first.

For finite HH, integrate before taking any limit: U(H)−U(0)=−∫0H(−5)dy=5HJ(H in m).\boxed{U(H)-U(0)=-\int_0^H(-5)dy=5H\ \mathrm J}\quad(H\text{ in m}).

(b) Test the proposed limiting assignment.

The proposed reference fails because limH→∞[U(H)−U(0)]=limH→∞5H=+∞.\lim_{H\to\infty}[U(H)-U(0)]=\lim_{H\to\infty}5H=+\infty. No finite constant yields finite potential at finite height and zero at infinity for this constant-force model.

(c) Choose a permissible datum.

A valid finite reference is U(0)=0U(0)=0: U(y)=5y,W2→5=U(2)−U(5)=10−25=−15J.U(y)=5y,\qquad\boxed{W_{2\to5}=U(2)-U(5)=10-25=-15\ \mathrm J}. Finite potential differences remain well defined.