Path Independence of Conservative Forces — Question 9

Section 8-2 · Physics pages 1048–1049

Question 9 Different loading and unloading curves A device is stretched quasistatically from x=0 to 0.20 m. The external force required is Fload = 100x N. On return it exerts a resisting magnitude described by an external holding force Funload = 60x N in the positive x direction. x (m) Fext (N) load unload 0.20 The shaded area represents the difference between the two force histories. (a) Find external-agent work on loading and unloading. (b) Find total external work over the cycle. (c) Can the device be described by a single potential depending only on x, if no other state is allowed?
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Question 9 - Solution Different loading and unloading curves x (m) Fext (N) load unload 0.20 (a) Keep the return displacement negative. Keep the unloading limits in their physical order: Wload = ∫.20 0 100x dx = 2.0 J , Wunload = ∫0 .20 60x dx = −1.2 J . (b) Compute the area between the histories. The net external work is the area between the loading histories: Wext,cycle = 2.0 −1.2 = 0.8 J . Negligible kinetic changes give Wdevice,cycle = −0.8 J. (c) Compare identical endpoint deformation. A single position potential would require Wdevice,cycle = −[U(0) −U(0)] = 0, contrary to the measured loop. The device requires dissipation or an additional internal state beyond extension alone.

Question 9

Different loading and unloading curves

A device is stretched quasistatically from x=0 to 0.20 m. The external force required is Fload=100xF_{\mathrm{load}}=100x N. On return it exerts a resisting magnitude described by an external holding force Funload=60xF_{\mathrm{unload}}=60x N in the positive x direction.

Diagram shown in the original SVG worksheet.

  1. Find external-agent work on loading and unloading.

  2. Find total external work over the cycle.

  3. Can the device be described by a single potential depending only on x, if no other state is allowed?

Question 9 - Solution

Different loading and unloading curves

Diagram shown in the original SVG worksheet.

(a) Keep the return displacement negative.

Keep the unloading limits in their physical order: Wload=∫0.20100xdx=2.0J,\boxed{W_{\mathrm{load}}=\int_0^{.20}100x\,dx=2.0\ \mathrm J}, Wunload=∫.20060xdx=−1.2J.\boxed{W_{\mathrm{unload}}=\int_{.20}^{0}60x\,dx=-1.2\ \mathrm J}.

(b) Compute the area between the histories.

The net external work is the area between the loading histories: Wext,cycle=2.0−1.2=0.8J.\boxed{W_{\mathrm{ext,cycle}}=2.0-1.2=0.8\ \mathrm J}. Negligible kinetic changes give Wdevice,cycle=−0.8W_{\mathrm{device,cycle}}=-0.8 J.

(c) Compare identical endpoint deformation.

A single position potential would require Wdevice,cycle=−[U(0)−U(0)]=0,W_{\mathrm{device,cycle}}=-[U(0)-U(0)]=0, contrary to the measured loop. The device requires dissipation or an additional internal state beyond extension alone.