Path Independence of Conservative Forces — Question 4

Section 8-2 · Physics pages 1038–1039

Question 4 Completing a conservative work network For a conservative interaction, WAB = 4 J, WBC = −10 J and WCD = 3 J. Points A, B, C and D are distinct configurations. A B C D 4 J −10 J 3 J Signed works add along consecutive directed paths. (a) Find WAC and WAD. (b) Find WDA and WDB. (c) An extra sensor reports WDB = 8 J exactly. Can all the data describe the stated conservative interaction?
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Question 4 - Solution Completing a conservative work network A B C D 4 J −10 J 3 J (a) Compose paths with common orientation. Conservative endpoint work composes along the chain: WAC = WAB + WBC = 4 −10 = −6 J , WAD = WAC + WCD = −6 + 3 = −3 J . (b) Reverse and reconnect. Reverse the full path and reconnect to B: WDA = −WAD = +3 J , WDB = WDA + WAB = 3 + 4 = 7 J . (c) Close a consistency loop. The additional exact reading produces WBC + WCD + WDB,reported = −10 + 3 + 8 = 1 J̸ = 0. The data cannot all describe the stipulated conservative interaction.

Question 4

Completing a conservative work network

For a conservative interaction, WAB=4W_{AB}=4 J, WBC=−10W_{BC}=-10 J and WCD=3W_{CD}=3 J. Points A, B, C and D are distinct configurations.

Diagram shown in the original SVG worksheet.

  1. Find WACW_{AC} and WADW_{AD}.

  2. Find WDAW_{DA} and WDBW_{DB}.

  3. An extra sensor reports WDB=8W_{DB}=8 J exactly. Can all the data describe the stated conservative interaction?

Question 4 - Solution

Completing a conservative work network

Diagram shown in the original SVG worksheet.

(a) Compose paths with common orientation.

Conservative endpoint work composes along the chain: WAC=WAB+WBC=4−10=−6J,\boxed{W_{AC}=W_{AB}+W_{BC}=4-10=-6\ \mathrm J}, WAD=WAC+WCD=−6+3=−3J.\boxed{W_{AD}=W_{AC}+W_{CD}=-6+3=-3\ \mathrm J}.

(b) Reverse and reconnect.

Reverse the full path and reconnect to B: WDA=−WAD=+3J,WDB=WDA+WAB=3+4=7J.\boxed{W_{DA}=-W_{AD}=+3\ \mathrm J},\qquad\boxed{W_{DB}=W_{DA}+W_{AB}=3+4=7\ \mathrm J}.

(c) Close a consistency loop.

The additional exact reading produces WBC+WCD+WDB,reported=−10+3+8=1J≠0.W_{BC}+W_{CD}+W_{DB,\mathrm{reported}}=-10+3+8=1\ \mathrm J\ne0. The data cannot all describe the stipulated conservative interaction.