Power — Question 4

Section 7-8 · Physics pages 998–999

Question 4 Constant power produces a square-root speed history A 2 kg cart begins at speed 3 m/s and receives a constant 10 W of net mechanical power for 4 s on a horizontal track. t (s) v (m/s) 3 vf 4 Speed rises while the force needed for the same power falls. (a) Find speed as a function of time and the final speed. (b) Find the driving force initially and finally, assuming it is parallel to velocity. (c) Explain why the same ideal constant-power force law cannot start smoothly from exact rest.
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Question 4 - Solution Constant power produces a square-root speed history t (s) v (m/s) 3 vf 4 (a) Integrate the energy rate. The governing relation is dK dt = P =⇒K(t) = K0 + Pt K(t) = K0 + Pt = 9 + 10t J. Since K = v2 here, v(t) = √ 9 + 10t m/s, v(4) = 7 m/s. (b) Divide power by instantaneous speed. F = P/v. Initially F = 10/3 N; finally F = 10/7 N. Constant power does not require constant force or acceleration. (c) Inspect the low-speed limit. For fixed positive P, F = P/v diverges as v approaches zero. A real drive must impose a finite force limit or ramp its power during startup; the given nonzero initial speed avoids the singularity.

Question 4

Constant power produces a square-root speed history

A 2 kg cart begins at speed 3 m/s and receives a constant 10 W of net mechanical power for 4 s on a horizontal track.

Diagram shown in the original SVG worksheet.

  1. Find speed as a function of time and the final speed.

  2. Find the driving force initially and finally, assuming it is parallel to velocity.

  3. Explain why the same ideal constant-power force law cannot start smoothly from exact rest.

Question 4 - Solution

Constant power produces a square-root speed history

Diagram shown in the original SVG worksheet.

(a) Integrate the energy rate.

The governing relation is dKdt=P⇒K(t)=K0+Pt\boxed{\frac{dK}{dt}=P\Longrightarrow K(t)=K_0+Pt}

K(t)=K0+Pt=9+10tJ.K(t)=K_0+Pt=9+10t\ \mathrm J. Since K=v2K=v^2 here, v(t)=9+10tm/s,v(4)=7m/s.v(t)=\sqrt{9+10t}\ \mathrm{m/s},\qquad v(4)=7\ \mathrm{m/s}.

(b) Divide power by instantaneous speed.

F=P/vF=P/v. Initially F=10/3N;F=10/3\ \mathrm N; finally F=10/7N.F=10/7\ \mathrm N. Constant power does not require constant force or acceleration.

(c) Inspect the low-speed limit.

For fixed positive P, F=P/vF=P/v diverges as v approaches zero. A real drive must impose a finite force limit or ramp its power during startup; the given nonzero initial speed avoids the singularity.