Work — Question 8

Section 7-3 · Physics pages 906–907

Question 8 A moving support can make a normal force do work For a constant force, use W =⃗F · ∆⃗r. A small block remains on a horizontal platform that translates without rotating. During one interval the platform and block move by (3, 2) m. The platform exerts a constant upward normal force of 8 N on the block. block N ∆⃗r Solid and dashed lines indicate initial and later platform levels schematically. (a) Find work by the normal force in the laboratory frame. (b) Find its work if instead the displacement were (3, 0) m. (c) What geometric condition makes work by a normal force zero?
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Question 8 - Solution A moving support can make a normal force do work block N ∆⃗r (a) Retain the vertical displacement. The governing relation is WN = Ny∆y for a constant vertical normal force⃗ N = (0, 8) N, so WN = 0(3) + 8(2) = 16 J. Contact does not prevent the supporting surface itself from moving. (b) Set the force-parallel displacement to zero. For (3, 0) m, WN = 0. (c) State the actual perpendicularity requirement. Work vanishes when the point receiving the normal force has no displacement component along that force, throughout the motion. This holds for sliding along a fixed rigid surface, but is not automatic for a moving support.

Question 8

A moving support can make a normal force do work

For a constant force, use W=F→⋅Δr→W=\vec F\cdot\Delta\vec r. A small block remains on a horizontal platform that translates without rotating. During one interval the platform and block move by (3,2)(3,2) m. The platform exerts a constant upward normal force of 8 N on the block.

Diagram shown in the original SVG worksheet.

  1. Find work by the normal force in the laboratory frame.

  2. Find its work if instead the displacement were (3,0)(3,0) m.

  3. What geometric condition makes work by a normal force zero?

Question 8 - Solution

A moving support can make a normal force do work

Diagram shown in the original SVG worksheet.

(a) Retain the vertical displacement.

The governing relation is WN=NyΔyfor a constant vertical normal force\boxed{W_N=N_y\Delta y\quad\text{for a constant vertical normal force}}

N→=(0,8)N,\vec N=(0,8)\ \mathrm N, so WN=0(3)+8(2)=16J.W_N=0(3)+8(2)=16\ \mathrm J. Contact does not prevent the supporting surface itself from moving.

(b) Set the force-parallel displacement to zero.

For (3,0)m(3,0)\ \mathrm m, WN=0W_N=0.

(c) State the actual perpendicularity requirement.

Work vanishes when the point receiving the normal force has no displacement component along that force, throughout the motion. This holds for sliding along a fixed rigid surface, but is not automatic for a moving support.