What Is Energy? — Question 3

Section 7-1 · Physics pages 856–857

Question 3 Steady energy does not mean no energy transfer For this introductory problem use the supplied accounting rule ∆E = Ein −Eout, with all quantities in joules. A lamp receives 600 J electrically during an observation interval. It emits 120 J as light and transfers 480 J thermally to its surroundings. Treat the lamp as the system. lamp 600 J 120 J light 480 J thermal Transfer arrows cross the lamp boundary; labels give energies, not rates. (a) Find its total energy change. (b) Explain why a zero change does not show the lamp is isolated. (c) If the light output stays 120 J but thermal transfer falls to 450 J, what additional change or transfer is required?
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Question 3 - Solution Steady energy does not mean no energy transfer lamp 600 J 120 J light 480 J thermal (a) Take the signed difference. The governing relation is ∆E = Eelectrical −Elight −Ethermal ∆E = 600 −120 −480 = 0 J. The system can have a steady energy store while energy flows through it. (b) Distinguish isolation from balance. An isolated system exchanges no energy with its surroundings. Here 600 J enters and 600 J leaves. Equal nonzero transfers are not absent transfers. (c) Close the revised ledger. With no other transfers, ∆E = 600 −120 −450 = 30 J. Alternatively, a further 30 J must leave if the lamp energy is to remain unchanged.

Question 3

Steady energy does not mean no energy transfer

For this introductory problem use the supplied accounting rule ΔE=Ein−Eout\Delta E=E_{\mathrm{in}}-E_{\mathrm{out}}, with all quantities in joules. A lamp receives 600 J electrically during an observation interval. It emits 120 J as light and transfers 480 J thermally to its surroundings. Treat the lamp as the system.

Diagram shown in the original SVG worksheet.

  1. Find its total energy change.

  2. Explain why a zero change does not show the lamp is isolated.

  3. If the light output stays 120 J but thermal transfer falls to 450 J, what additional change or transfer is required?

Question 3 - Solution

Steady energy does not mean no energy transfer

Diagram shown in the original SVG worksheet.

(a) Take the signed difference.

The governing relation is ΔE=Eelectrical−Elight−Ethermal\boxed{\Delta E=E_{\mathrm{electrical}}-E_{\mathrm{light}}-E_{\mathrm{thermal}}}

ΔE=600−120−480=0J.\Delta E=600-120-480=0\ \mathrm J. The system can have a steady energy store while energy flows through it.

(b) Distinguish isolation from balance.

An isolated system exchanges no energy with its surroundings. Here 600 J enters and 600 J leaves. Equal nonzero transfers are not absent transfers.

(c) Close the revised ledger.

With no other transfers, ΔE=600−120−450=30J.\Delta E=600-120-450=30\ \mathrm J. Alternatively, a further 30 J must leave if the lamp energy is to remain unchanged.