Properties of Friction — Question 4

Section 6-2 · Physics pages 798–799

Question 4 Two acceleration measurements isolate friction and an unknown pull Take g = 10 m/s2. Use ideal dry friction, |fs| ≤µsN and |fk| = µkN. A 4 kg block slides right on a level floor under the same constant horizontal pull P in two trials. With no added load its acceleration is 3 m/s2. With a firmly attached 2 kg payload its acceleration is 1 m/s2. Both trials share one kinetic coefficient. 4 kg P a = 3 m/s2 4 kg 2 kg P a = 1 m/s2 The same rightward pull acts in both trials; the attached payload changes both inertia and normal load. (a) Write the two force equations. (b) Infer P and µk. (c) Predict acceleration with a 4 kg payload and state what cannot be inferred about starting from rest.
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Question 4 - Solution Two acceleration measurements isolate friction and an unknown pull 4 kg P a = 3 m/s2 4 kg 2 kg P a = 1 m/s2 (a) Account for both inertia and normal load. For each trial, N = Mg and P −µkMg = Ma. Thus P −40µk = 12 N , P −60µk = 6 N . The payload changes both the normal force and inertial mass. (b) Eliminate the common pull. Subtract the equations to eliminate the common pull: (P −40µk) −(P −60µk) = 12 −6 =⇒20µk = 6. µk = .30 , P = 12 + 40(.30) = 24 N . (c) Predict only within the tested regime. A 4 kg payload makes the total mass 8 kg: a = 24 −(.30)(8)(10) 8 = 0 . The rightward-sliding block coasts at constant speed. Starting from rest would require P > µsMg, and these kinetic measurements do not determine µs.

Question 4

Two acceleration measurements isolate friction and an unknown pull

Take g=10g=10 m/s2^2. Use ideal dry friction, |fs|≤μsN|f_s|\le\mu_sN and |fk|=μkN|f_k|=\mu_kN. A 4 kg block slides right on a level floor under the same constant horizontal pull P in two trials. With no added load its acceleration is 3 m/s2^2. With a firmly attached 2 kg payload its acceleration is 1 m/s2^2. Both trials share one kinetic coefficient.

Diagram shown in the original SVG worksheet.

  1. Write the two force equations.

  2. Infer P and μk\mu_k.

  3. Predict acceleration with a 4 kg payload and state what cannot be inferred about starting from rest.

Question 4 - Solution

Two acceleration measurements isolate friction and an unknown pull

Diagram shown in the original SVG worksheet.

(a) Account for both inertia and normal load.

For each trial, N=MgN=Mg and P−μkMg=MaP-\mu_kMg=Ma. Thus P−40μk=12N,P−60μk=6N.\boxed{P-40\mu_k=12\ \mathrm N},\qquad\boxed{P-60\mu_k=6\ \mathrm N}. The payload changes both the normal force and inertial mass.

(b) Eliminate the common pull.

Subtract the equations to eliminate the common pull: (P−40μk)−(P−60μk)=12−6⇒20μk=6.(P-40\mu_k)-(P-60\mu_k)=12-6\Longrightarrow20\mu_k=6. μk=.30,P=12+40(.30)=24N.\boxed{\mu_k=.30},\qquad\boxed{P=12+40(.30)=24\ \mathrm N}.

(c) Predict only within the tested regime.

A 4 kg payload makes the total mass 8 kg: a=24−(.30)(8)(10)8=0.\boxed{a=\frac{24-(.30)(8)(10)}8=0}. The rightward-sliding block coasts at constant speed. Starting from rest would require P>μsMgP>\mu_sMg, and these kinetic measurements do not determine μs\mu_s.