Newton's Third Law — Question 6

Section 5-7 · Physics pages 742–743

Question 6 A trailer reaction does not cancel external traction A motorized cart pulls a trailer along level ground at constant speed. Ground pushes the cart forward with 500 N. Ground and air together resist the trailer with 300 N and the cart with 200 N. cart trailer forward Forward is left in this schematic; use the stated forward-positive signs in the equations. (a) Find the tow-link force on the trailer. (b) List the horizontal forces on the cart and verify balance. (c) Why does the trailer’s backward pull not prevent forward travel?
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Question 6 - Solution A trailer reaction does not cancel external traction cart trailer forward (a) Balance the trailer. T −300 = 0 ⇒ T = 300 N The tow link pulls the trailer forward with 300 N to balance its 300 N resistance. (b) Include traction and both backward forces. Fnet,C = 500 −200 −T = 500 −200 −300 = 0 N The cart experiences +500 N traction, -200 N resistance and -300 N from the trailer, summing to zero. (c) Use the whole interaction inventory. Fext,C+T = 500 −200 −300 = 0 ⇒v = constant The trailer’s pull is real, but ground traction supplies an external forward force. For the combined system the tow-link pair is internal and cancels; external forces sum to 500 −200 −300 = 0, consistent with constant forward velocity.

Question 6

A trailer reaction does not cancel external traction

A motorized cart pulls a trailer along level ground at constant speed. Ground pushes the cart forward with 500 N. Ground and air together resist the trailer with 300 N and the cart with 200 N.

Diagram shown in the original SVG worksheet.

  1. Find the tow-link force on the trailer.

  2. List the horizontal forces on the cart and verify balance.

  3. Why does the trailer’s backward pull not prevent forward travel?

Question 6 - Solution

A trailer reaction does not cancel external traction

Diagram shown in the original SVG worksheet.

(a) Balance the trailer.

T−300=0⇒T=300NT-300=0\ \Rightarrow\ \boxed{T=300\,\mathrm N} The tow link pulls the trailer forward with 300 N to balance its 300 N resistance.

(b) Include traction and both backward forces.

Fnet,C=500−200−T=500−200−300=0NF_{{\mathrm{net}},C}=500-200-T=500-200-300=0\,\mathrm N The cart experiences +500 N traction, -200 N resistance and -300 N from the trailer, summing to zero.

(c) Use the whole interaction inventory.

Fext,C+T=500−200−300=0⇒v=constantF_{{\mathrm{ext}},C+T}=500-200-300=0\ \Rightarrow\ v=\text{constant} The trailer’s pull is real, but ground traction supplies an external forward force. For the combined system the tow-link pair is internal and cancels; external forces sum to 500−200−300=0500-200-300=0, consistent with constant forward velocity.