Newton's First Law — Question 3

Section 5-2 · Physics pages 636–637

Question 3 Straightness and uniform speed are separate tests Three planar motions are observed in an inertial frame: A moves east at constant 4 m/s; B moves east with increasing speed; C travels around a circle at constant 4 m/s. A C A straight track and a curved track can have the same speed but different acceleration. (a) Which motion is compatible with zero net force throughout? (b) For B and C, identify what changes in the velocity vector. (c) Does an unchanged speed alone establish balanced forces?
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Question 3 - Solution Straightness and uniform speed are separate tests A C (a) Test constant vector velocity.⃗ aA = d(4ˆi) dt =⃗0,⃗ Fnet,A =⃗0 Only A has constant velocity and is compatible with zero resultant force throughout. B and C each have acceleration. (b) Separate magnitude and direction.⃗ a = ˙v ˆt + vdˆt dt : ˙vB > 0, |⃗aC| = 42 r > 0 B changes the magnitude of its eastward velocity. C keeps the magnitude but turns the direction continuously, so its velocity changes as well. (c) Use both vector attributes. d|⃗v| dt = 0̸ ⇒d⃗v dt =⃗0 No. Constant speed does not imply constant velocity. The first-law condition concerns a straight, constant-speed trajectory, including rest as the zero-velocity case, in an inertial frame.

Question 3

Straightness and uniform speed are separate tests

Three planar motions are observed in an inertial frame: A moves east at constant 4 m/s; B moves east with increasing speed; C travels around a circle at constant 4 m/s.

Diagram shown in the original SVG worksheet.

  1. Which motion is compatible with zero net force throughout?

  2. For B and C, identify what changes in the velocity vector.

  3. Does an unchanged speed alone establish balanced forces?

Question 3 - Solution

Straightness and uniform speed are separate tests

Diagram shown in the original SVG worksheet.

(a) Test constant vector velocity.

a→A=d(4î)dt=0→,F→net,A=0→\vec a_A=\frac{d(4\hat i)}{dt}=\vec0,\quad\boxed{\vec F_{{\mathrm{net}},A}=\vec0} Only A has constant velocity and is compatible with zero resultant force throughout. B and C each have acceleration.

(b) Separate magnitude and direction.

a→=v̇t̂+vdt̂dt:v̇B>0,|a→C|=42r>0\vec a=\dot v\,\hat t+v\frac{d\hat t}{dt}:\quad\dot v_B>0,\quad |\vec a_C|=\frac{4^2}{r}>0 B changes the magnitude of its eastward velocity. C keeps the magnitude but turns the direction continuously, so its velocity changes as well.

(c) Use both vector attributes.

d|v→|dt=0⇏dv→dt=0→\frac{d|\vec v|}{dt}=0\ \not\Rightarrow\ \frac{d\vec v}{dt}=\vec0 No. Constant speed does not imply constant velocity. The first-law condition concerns a straight, constant-speed trajectory, including rest as the zero-velocity case, in an inertial frame.