A Pause for Reflection — Question 1

Section 44-9 · Physics pages 7452–7453

Question 1 Missing four-momentum tests an invisible-particle hypothesis In a collider center-of-mass frame use c=1. Initial four-momentum is (10, 0) GeV. The entire visible system has energy 6 GeV and momentum (0, 0, 3) GeV. visible visible inferred Schematic; labels, not drawing lengths, specify the data. (a) Find the missing four-momentum and invariant mass. (b) Determine whether the missing system could be exactly one massless neutrino; state an allowed alternative.
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Question 1 - Solution Missing four-momentum tests an invisible-particle hypothesis visible visible inferred (a) Method and calculation Pmiss = (4, 0, 0, −3) GeV . mmiss = √ 42 −32 = √ 7 = 2.646 GeV . (b) Interpretation and further calculation One massless particle requires E2 miss −|pmiss|2 = 0. m2 miss = 7 > 0 : one massless neutrino is excluded . Physical check Multiple noncollinear massless particles can have positive combined invariant mass; so can one massive invisible particle. Detector losses must also be considered.

Question 1

Missing four-momentum tests an invisible-particle hypothesis

In a collider center-of-mass frame use c=1. Initial four-momentum is (10,𝟎)(10,\mathbf0) GeV. The entire visible system has energy 6 GeV and momentum (0,0,3)(0,0,3) GeV.

Diagram shown in the original SVG worksheet.

  1. Find the missing four-momentum and invariant mass.

  2. Determine whether the missing system could be exactly one massless neutrino; state an allowed alternative.

Question 1 - Solution

Missing four-momentum tests an invisible-particle hypothesis

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Pmiss=(4,0,0,−3)GeV.\boxed{P_{\mathrm{miss}}=(4,0,0,-3)\ {\mathrm{GeV}}}.mmiss=42−32=7=2.646GeV.\boxed{m_{\mathrm{miss}}=\sqrt{4^2-3^2}=\sqrt7=2.646\ {\mathrm{GeV}}}.

(b) Interpretation and further calculation

One massless particle requires Emiss2−|𝒑miss|2=0.\text{One massless particle requires }E_{\mathrm{miss}}^2-|\mathbf p_{\mathrm{miss}}|^2=0.mmiss2=7>0:one massless neutrino is excluded.\boxed{m_{\mathrm{miss}}^2=7>0:\ \text{one massless neutrino is excluded}}.

Physical check

Multiple noncollinear massless particles can have positive combined invariant mass; so can one massive invisible particle. Detector losses must also be considered.