The Quark Model — Question 1

Section 44-7 · Physics pages 7412–7413

Question 1 Reconstructing valence counts from a baryon charge A nonstrange three-quark baryon contains only u and d quarks. Their charges are +2e/3 and −e/3, and each has B=1/3. Its total charge is +e. u u d Schematic; labels, not drawing lengths, specify the data. (a) Solve simultaneously for the numbers of u and d valence quarks. (b) Repeat for a neutral baryon and determine the antiquark content of its antiparticle.
Show solutionHide solution
Question 1 - Solution Reconstructing valence counts from a baryon charge u u d (a) Method and calculation Nu + Nd = 3, (2Nu −Nd)/3 = 1. Nu = 2, Nd = 1 : uud, B = 1 . (b) Interpretation and further calculation Q = 0 ⇒2Nu = Nd ⇒udd . ¯u ¯d ¯d : Q = 0, B = −1 . Physical check Valence counts specify net flavor. Real hadrons also contain gluons and quark-antiquark sea components.

Question 1

Reconstructing valence counts from a baryon charge

A nonstrange three-quark baryon contains only u and d quarks. Their charges are +2e/3+2e/3 and −e/3-e/3, and each has B=1/3. Its total charge is +e.

Diagram shown in the original SVG worksheet.

  1. Solve simultaneously for the numbers of u and d valence quarks.

  2. Repeat for a neutral baryon and determine the antiquark content of its antiparticle.

Question 1 - Solution

Reconstructing valence counts from a baryon charge

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Nu+Nd=3,(2Nu−Nd)/3=1.N_u+N_d=3,\quad(2N_u-N_d)/3=1.Nu=2,Nd=1:uud,B=1.\boxed{N_u=2,\ N_d=1:\ uud,\quad B=1}.

(b) Interpretation and further calculation

Q=0⇒2Nu=Nd⇒udd.Q=0\Rightarrow 2N_u=N_d\Rightarrow\boxed{udd}.u‾d‾d‾:Q=0,B=−1.\boxed{\bar u\bar d\bar d:\quad Q=0,\ B=-1}.

Physical check

Valence counts specify net flavor. Real hadrons also contain gluons and quark-antiquark sea components.