The Eightfold Way — Question 10

Section 44-6 · Physics pages 7410–7411

Question 10 Representation dimension counts flavor weights with multiplicity For an SU(3) representation labeled by nonnegative integers (p,q), its dimension is d = (p + 1)(q + 1)(p + q + 2)/2. Consider (1,1), (3,0) and (0,3). Y I3 ∆− ∆0 ∆+ ∆++ Σ∗− Σ∗0 Σ∗+ Ξ∗− Ξ∗0 Ω− Light-flavor weight diagram: horizontal coordinate I3, vertical coordinate Y = B + S; axis origins are offset for clarity. (a) Calculate each dimension and identify the octet and decuplet dimensions. (b) If every flavor state in the (3,0) representation has spatial spin 3/2, count flavor-spin basis states and explain why equal dimension does not equate (3,0) with (0,3).
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Question 10 - Solution Representation dimension counts flavor weights with multiplicity Y I3 ∆− ∆0 ∆+ ∆++ Σ∗− Σ∗0 Σ∗+ Ξ∗− Ξ∗0 Ω− (a) Method and calculation d(1, 1) = 2(2)(4)/2 = 8 . d(3, 0) = 4(1)(5)/2 = 10 = d(0, 3) . (b) Interpretation and further calculation Nflavor,spin = 10(2J + 1) = 10(4) = 40 . (3, 0)̸ = (0, 3), equal dimension does not imply identical weights . Physical check The dimension formula counts internal flavor states, including repeated weights. It does not determine spatial spin or the masses.

Question 10

Representation dimension counts flavor weights with multiplicity

For an SU(3) representation labeled by nonnegative integers (p,q), its dimension is d=(p+1)(q+1)(p+q+2)/2d=(p+1)(q+1)(p+q+2)/2. Consider (1,1), (3,0) and (0,3).

Diagram shown in the original SVG worksheet.

  1. Calculate each dimension and identify the octet and decuplet dimensions.

  2. If every flavor state in the (3,0) representation has spatial spin 3/2, count flavor-spin basis states and explain why equal dimension does not equate (3,0) with (0,3).

Question 10 - Solution

Representation dimension counts flavor weights with multiplicity

Diagram shown in the original SVG worksheet.

(a) Method and calculation

d(1,1)=2(2)(4)/2=8.\boxed{d(1,1)=2(2)(4)/2=8}.d(3,0)=4(1)(5)/2=10=d(0,3).\boxed{d(3,0)=4(1)(5)/2=10=d(0,3)}.

(b) Interpretation and further calculation

Nflavor,spin=10(2J+1)=10(4)=40.\boxed{N_{\mathrm{flavor,spin}}=10(2J+1)=10(4)=40}.(3,0)≠(0,3),equal dimension does not imply identical weights.(3,0)\ne(0,3),\quad\boxed{\text{equal dimension does not imply identical weights}}.

Physical check

The dimension formula counts internal flavor states, including repeated weights. It does not determine spatial spin or the masses.