The Eightfold Way — Question 4

Section 44-6 · Physics pages 7398–7399

Question 4 Antiparticle reflection organizes the pseudoscalar meson octet An ideal light meson octet contains a kaon doublet at Y=+1, an antikaon doublet at Y=-1, a pion triplet at Y=0 and an eta singlet at Y=0. B=0 throughout. Y I3 K0 K+ π− π0, η8 π+ K− ¯K0 Light-flavor weight diagram: horizontal coordinate I3, vertical coordinate Y = B + S; axis origins are offset for clarity. (a) Find charges for the doublets and count all states. (b) Under charge conjugation, show how a weight changes and identify the partner of K+ at (I3, Y ) = (1/2, 1).
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Question 4 - Solution Antiparticle reflection organizes the pseudoscalar meson octet Y I3 K0 K+ π− π0, η8 π+ K− ¯K0 (a) Method and calculation Y = +1 : Q/e = (0, 1); Y = −1 : Q/e = (−1, 0). N = 2 + 2 + 3 + 1 = 8 . (b) Interpretation and further calculation (I3, Y, Q) 7→(−I3, −Y, −Q) . K+ : (1/2, 1) 7→K−: (−1/2, −1) . Physical check The eta here is an ideal octet state; physical neutral mesons can mix. Charge conjugation preserves baryon number zero.

Question 4

Antiparticle reflection organizes the pseudoscalar meson octet

An ideal light meson octet contains a kaon doublet at Y=+1, an antikaon doublet at Y=-1, a pion triplet at Y=0 and an eta singlet at Y=0. B=0 throughout.

Diagram shown in the original SVG worksheet.

  1. Find charges for the doublets and count all states.

  2. Under charge conjugation, show how a weight changes and identify the partner of K+K^+ at (I3,Y)=(1/2,1)(I_3,Y)=(1/2,1).

Question 4 - Solution

Antiparticle reflection organizes the pseudoscalar meson octet

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Y=+1:Q/e=(0,1);Y=−1:Q/e=(−1,0).Y=+1:\ Q/e=(0,1);\quad Y=-1:\ Q/e=(-1,0).N=2+2+3+1=8.\boxed{N=2+2+3+1=8}.

(b) Interpretation and further calculation

(I3,Y,Q)↦(−I3,−Y,−Q).\boxed{(I_3,Y,Q)\mapsto(-I_3,-Y,-Q)}.K+:(1/2,1)↦K−:(−1/2,−1).\boxed{K^+:(1/2,1)\mapsto K^-:(-1/2,-1)}.

Physical check

The eta here is an ideal octet state; physical neutral mesons can mix. Charge conjugation preserves baryon number zero.