The Eightfold Way — Question 2

Section 44-6 · Physics pages 7394–7395

Question 2 A shared neutral weight does not identify a unique baryon The Sigma triplet has I=1, B=1, S=-1. The Lambda has I=0 with the same B and S. Use Q/e = I3 + (B + S)/2. Y I3 n p Σ− Σ0, Λ Σ+ Ξ− Ξ0 Light-flavor weight diagram: horizontal coordinate I3, vertical coordinate Y = B + S; axis origins are offset for clarity. (a) Find all Sigma charges and the Lambda charge. (b) Explain why a point at I3 = Y = 0 contains two distinct octet states.
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Question 2 - Solution A shared neutral weight does not identify a unique baryon Y I3 n p Σ− Σ0, Λ Σ+ Ξ− Ξ0 (a) Method and calculation Y = 1 −1 = 0, I3(Σ) = −1, 0, +1 . Q(Σ) = −e, 0, +e; Q(Λ) = 0 . (b) Interpretation and further calculation I2|Σ0⟩= 1(1 + 1)|Σ0⟩, I2|Λ⟩= 0. (I3, Y ) = (0, 0) has multiplicity 2 . Physical check Here I is dimensionless internal isospin. The distinct eigenvalues of its squared operator distinguish the neutral states.

Question 2

A shared neutral weight does not identify a unique baryon

The Sigma triplet has I=1, B=1, S=-1. The Lambda has I=0 with the same B and S. Use Q/e=I3+(B+S)/2Q/e=I_3+(B+S)/2.

Diagram shown in the original SVG worksheet.

  1. Find all Sigma charges and the Lambda charge.

  2. Explain why a point at I3=Y=0I_3=Y=0 contains two distinct octet states.

Question 2 - Solution

A shared neutral weight does not identify a unique baryon

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Y=1−1=0,I3(Σ)=−1,0,+1.\boxed{Y=1-1=0,\quad I_3(\Sigma)=-1,0,+1}.Q(Σ)=−e,0,+e;Q(Λ)=0.\boxed{Q(\Sigma)=-e,0,+e;\quad Q(\Lambda)=0}.

(b) Interpretation and further calculation

I2|Σ0⟩=1(1+1)|Σ0⟩,I2|Λ⟩=0.I^2|\Sigma^0\rangle=1(1+1)|\Sigma^0\rangle,\quad I^2|\Lambda\rangle=0.(I3,Y)=(0,0) has multiplicity 2.\boxed{(I_3,Y)=(0,0)\text{ has multiplicity }2}.

Physical check

Here I is dimensionless internal isospin. The distinct eigenvalues of its squared operator distinguish the neutral states.