Still Another Conservation Law — Question 10

Section 44-5 · Physics pages 7390–7391

Question 10 Strangeness conservation is a necessary test rather than a complete mechanism label Two hypothetical transitions conserve electric charge, baryon number and energy. A changes strangeness by +1. B has Delta S=0. Their amplitudes are not supplied. As Aw Schematic; labels, not drawing lengths, specify the data. (a) State what follows about strong and electromagnetic mechanisms for A and B. (b) In a model for B, strong and weak amplitudes are As = 1 and Aw = .020eiϕ in common units. Find the extreme total rate factors relative to |As|2.
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Question 10 - Solution Strangeness conservation is a necessary test rather than a complete mechanism label As Aw (a) Method and calculation ∆SA = +1 ⇒As = Aem = 0 for a strangeness-changing transition. ∆SB = 0 does not exclude a weak contribution or guarantee a strong one. (b) Interpretation and further calculation |As + Aw|2 = 1 + .0202 + .040 cos ϕ. Rmin = .9802 = .9604, Rmax = 1.0202 = 1.0404 . Physical check A selection rule can exclude an interaction but cannot by itself determine all allowed amplitudes. Coherent contributions interfere when they connect the same states.

Question 10

Strangeness conservation is a necessary test rather than a complete mechanism label

Two hypothetical transitions conserve electric charge, baryon number and energy. A changes strangeness by +1. B has Delta S=0. Their amplitudes are not supplied.

Diagram shown in the original SVG worksheet.

  1. State what follows about strong and electromagnetic mechanisms for A and B.

  2. In a model for B, strong and weak amplitudes are As=1A_s=1 and Aw=.020eiϕA_w=.020e^{i\phi} in common units. Find the extreme total rate factors relative to |As|2|A_s|^2.

Question 10 - Solution

Strangeness conservation is a necessary test rather than a complete mechanism label

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ΔSA=+1⇒As=Aem=0for a strangeness-changing transition.\boxed{\Delta S_A=+1\Rightarrow A_s=A_{\mathrm{em}}=0}\quad\text{for a strangeness-changing transition}.ΔSB=0does not exclude a weak contribution or guarantee a strong one.\boxed{\Delta S_B=0}\quad\text{does not exclude a weak contribution or guarantee a strong one}.

(b) Interpretation and further calculation

|As+Aw|2=1+.0202+.040cos⁡ϕ.|A_s+A_w|^2=1+.020^2+.040\cos\phi.Rmin=.9802=.9604,Rmax=1.0202=1.0404.\boxed{R_{\min}=.980^2=.9604,\quad R_{\max}=1.020^2=1.0404}.

Physical check

A selection rule can exclude an interaction but cannot by itself determine all allowed amplitudes. Coherent contributions interfere when they connect the same states.