The Hadrons — Question 7

Section 44-4 · Physics pages 7364–7365

Question 7 Inclusive scattering infers a hadronic mass without observing every fragment A stationary target has rest energy 1.00 GeV. A probe transfers energy nu=.500 GeV and momentum magnitude q with qc=.800 GeV. Use W 2 = (mc2 + ν)2 −q2c2. probe + target probe + hadronic system W Schematic; labels, not drawing lengths, specify the data. (a) Find the invariant mass energy of the produced hadronic system. (b) Can a final state with minimum total rest energy 1.20 GeV be produced? Find its available center-of-mass kinetic energy.
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Question 7 - Solution Inclusive scattering infers a hadronic mass without observing every fragment probe + target probe + hadronic system W (a) Method and calculation Q2 = q2c2 −ν2 = .640 −.250 = .390 GeV2. W = √ m2c4 + 2mc2ν −Q2 = √ 1.610 = 1.26886 GeV . (b) Interpretation and further calculation W > 1.20 GeV ⇒kinematically accessible . Kavailable = W −1.20 = .068858 GeV . Physical check The final invariant mass is not simply target rest energy plus transferred energy; net recoil momentum must be removed.

Question 7

Inclusive scattering infers a hadronic mass without observing every fragment

A stationary target has rest energy 1.00 GeV. A probe transfers energy nu=.500 GeV and momentum magnitude q with qc=.800 GeV. Use W2=(mc2+ν)2−q2c2W^2=(mc^2+\nu)^2-q^2c^2.

Diagram shown in the original SVG worksheet.

  1. Find the invariant mass energy of the produced hadronic system.

  2. Can a final state with minimum total rest energy 1.20 GeV be produced? Find its available center-of-mass kinetic energy.

Question 7 - Solution

Inclusive scattering infers a hadronic mass without observing every fragment

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Q2=q2c2−ν2=.640−.250=.390GeV2.Q^2=q^2c^2-\nu^2=.640-.250=.390\,\mathrm{GeV^2}.W=m2c4+2mc2ν−Q2=1.610=1.26886GeV.\boxed{W=\sqrt{m^2c^4+2mc^2\nu-Q^2}=\sqrt{1.610}=1.26886\,\mathrm{GeV}}.

(b) Interpretation and further calculation

W>1.20GeV⇒kinematically accessible.\boxed{W>1.20\,\mathrm{GeV}\Rightarrow\text{kinematically accessible}}.Kavailable=W−1.20=.068858GeV.\boxed{K_{\mathrm{available}}=W-1.20=.068858\,\mathrm{GeV}}.

Physical check

The final invariant mass is not simply target rest energy plus transferred energy; net recoil momentum must be removed.