The Hadrons — Question 2

Section 44-4 · Physics pages 7354–7355

Question 2 Pion production on a stationary proton pays a recoil-energy penalty Consider p + p →p + p + π0 with one initial proton at rest. Use mpc2 = 1.00 GeV and mπc2 = .140 GeV for this model. p + p p + p + π0 Schematic; labels, not drawing lengths, specify the data. (a) Derive the threshold kinetic energy of the incident proton. (b) Evaluate it and compare it with the pion rest energy.
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Question 2 - Solution Pion production on a stationary proton pays a recoil-energy penalty p + p p + p + π0 (a) Method and calculation W 2 = 4m2 pc4 + 2mpc2K, Wth = (2mp + mπ)c2. Kth = 2mπc2 + m2 π 2mp c2 . (b) Interpretation and further calculation Kth = .280 + .0196/2 = .2898 GeV . Kth/(mπc2) = 2.07 > 1 . Physical check At threshold the three final particles are at rest relative to one another, not relative to the lab. Initial momentum consumes part of the available energy.

Question 2

Pion production on a stationary proton pays a recoil-energy penalty

Consider p+p→p+p+π0p+p\to p+p+\pi^0 with one initial proton at rest. Use mpc2=1.00m_pc^2=1.00 GeV and mπc2=.140m_\pi c^2=.140 GeV for this model.

Diagram shown in the original SVG worksheet.

  1. Derive the threshold kinetic energy of the incident proton.

  2. Evaluate it and compare it with the pion rest energy.

Question 2 - Solution

Pion production on a stationary proton pays a recoil-energy penalty

Diagram shown in the original SVG worksheet.

(a) Method and calculation

W2=4mp2c4+2mpc2K,Wth=(2mp+mπ)c2.W^2=4m_p^2c^4+2m_pc^2K,\quad W_{\mathrm{th}}=(2m_p+m_\pi)c^2.Kth=2mπc2+mπ22mpc2.\boxed{K_{\mathrm{th}}=2m_\pi c^2+\frac{m_\pi^2}{2m_p}c^2}.

(b) Interpretation and further calculation

Kth=.280+.0196/2=.2898GeV.\boxed{K_{\mathrm{th}}=.280+.0196/2=.2898\,\mathrm{GeV}}.Kth/(mπc2)=2.07>1.\boxed{K_{\mathrm{th}}/(m_\pi c^2)=2.07>1}.

Physical check

At threshold the three final particles are at rest relative to one another, not relative to the lab. Initial momentum consumes part of the available energy.