The Leptons — Question 10

Section 44-3 · Physics pages 7350–7351

Question 10 Charged-current detection identifies the incident neutrino flavor In a simplified detector, νµ + n →µ−+ p and ¯νµ + p →µ+ + n are the only selected channels. A sample contains 600 negative-muon events and 100 positive-muon events. Efficiencies are .600 and .500. Exposures and cross sections are assumed equal. neutrino beam µ− µ+ Schematic; labels, not drawing lengths, specify the data. (a) Infer the neutrino-to-antineutrino incident-flux ratio. (b) Check charge and muon-family number for each channel, and explain the limitation if cross sections differ.
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Question 10 - Solution Charged-current detection identifies the incident neutrino flavor neutrino beam µ− µ+ (a) Method and calculation Nν ∝600/.600 = 1000, N¯ν ∝100/.500 = 200 . Φν/Φ¯ν = 5.00 under equal cross sections and exposures. (b) Interpretation and further calculation νµn : Q = 0 = −1 + 1, Lµ = 1 = 1; ¯νµp : Q = 1 = 1 + 0, Lµ = −1 = −1. Φν Φ¯ν = C−/ϵ− C+/ϵ+ σ¯ν σν for equal target exposures. Physical check The sign of the charged muon tags neutrino versus antineutrino in these selected channels. Equal cross sections are a teaching assumption, not a general fact.

Question 10

Charged-current detection identifies the incident neutrino flavor

In a simplified detector, νμ+n→μ−+p\nu_\mu+n\to\mu^-+p and ν‾μ+p→μ++n\bar\nu_\mu+p\to\mu^++n are the only selected channels. A sample contains 600 negative-muon events and 100 positive-muon events. Efficiencies are .600 and .500. Exposures and cross sections are assumed equal.

Diagram shown in the original SVG worksheet.

  1. Infer the neutrino-to-antineutrino incident-flux ratio.

  2. Check charge and muon-family number for each channel, and explain the limitation if cross sections differ.

Question 10 - Solution

Charged-current detection identifies the incident neutrino flavor

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Nν∝600/.600=1000,Nν‾∝100/.500=200.\boxed{N_\nu\propto600/.600=1000,\quad N_{\bar\nu}\propto100/.500=200}.Φν/Φν‾=5.00under equal cross sections and exposures.\boxed{\Phi_\nu/\Phi_{\bar\nu}=5.00}\quad\text{under equal cross sections and exposures}.

(b) Interpretation and further calculation

νμn:Q=0=−1+1,Lμ=1=1;ν‾μp:Q=1=1+0,Lμ=−1=−1.\nu_\mu n:\ Q=0=-1+1,\ L_\mu=1=1;\quad\bar\nu_\mu p:\ Q=1=1+0,\ L_\mu=-1=-1.ΦνΦν‾=C−/ϵ−C+/ϵ+σν‾σνfor equal target exposures.\boxed{\frac{\Phi_\nu}{\Phi_{\bar\nu}}=\frac{C_-/\epsilon_-}{C_+/\epsilon_+}\frac{\sigma_{\bar\nu}}{\sigma_\nu}}\quad\text{for equal target exposures}.

Physical check

The sign of the charged muon tags neutrino versus antineutrino in these selected channels. Equal cross sections are a teaching assumption, not a general fact.