A Summing Up — Question 1

Section 44-14 · Physics pages 7552–7553

Question 1 A relic annihilation rate connects a particle cross section to cosmic dilution After a species becomes nonrelativistic, assume its conserved number density scales as n ∝a−3 and its constant annihilation coefficient is ⟨σv⟩. During radiation domination H ∝a−2. Initially Γ/H = 8, with Γ = n⟨σv⟩. t hot decoupling today Schematic; labels, not drawing lengths, specify the data. (a) Derive how Gamma/H scales with a and find the expansion factor at which it reaches one. (b) At that point find the number-density and Hubble-rate ratios relative to their initial values.
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Question 1 - Solution A relic annihilation rate connects a particle cross section to cosmic dilution t hot decoupling today (a) Method and calculation Γ/H ∝a−3/a−2 = a−1 . 1 = 8(ai/af) ⇒af/ai = 8 . (b) Interpretation and further calculation nf/ni = 8−3 = 1/512 . Hf/Hi = 8−2 = 1/64, (Γ/H)f = 8(64/512) = 1 . Physical check Conserved abundance is a post-equilibrium scaling assumption. A full relic calculation evolves annihilation and production together rather than imposing fixed comoving number through freeze-out.

Question 1

A relic annihilation rate connects a particle cross section to cosmic dilution

After a species becomes nonrelativistic, assume its conserved number density scales as n∝a−3n\propto a^{-3} and its constant annihilation coefficient is ⟨σv⟩\langle\sigma v\rangle. During radiation domination H∝a−2H\propto a^{-2}. Initially Γ/H=8\Gamma/H=8, with Γ=n⟨σv⟩\Gamma=n\langle\sigma v\rangle.

Diagram shown in the original SVG worksheet.

  1. Derive how Gamma/H scales with a and find the expansion factor at which it reaches one.

  2. At that point find the number-density and Hubble-rate ratios relative to their initial values.

Question 1 - Solution

A relic annihilation rate connects a particle cross section to cosmic dilution

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Γ/H∝a−3/a−2=a−1.\Gamma/H\propto a^{-3}/a^{-2}=\boxed{a^{-1}}.1=8(ai/af)⇒af/ai=8.1=8(a_i/a_f)\Rightarrow\boxed{a_f/a_i=8}.

(b) Interpretation and further calculation

nf/ni=8−3=1/512.\boxed{n_f/n_i=8^{-3}=1/512}.Hf/Hi=8−2=1/64,(Γ/H)f=8(64/512)=1.\boxed{H_f/H_i=8^{-2}=1/64,\quad(\Gamma/H)_f=8(64/512)=1}.

Physical check

Conserved abundance is a post-equilibrium scaling assumption. A full relic calculation evolves annihilation and production together rather than imposing fixed comoving number through freeze-out.