The Big Bang — Question 10

Section 44-13 · Physics pages 7550–7551

Question 10 Independent abundance measurements test a shared cosmic baryon density In an illustrative nucleosynthesis model, deuterium abundance is D/H = 2.5 × 10−5(6/η10)1.6, where η10 = 1010η. An observation gives D/H = 3.0 × 10−5. An independent background fit gives η10 = 6.0. η10 D/H Schematic; labels, not drawing lengths, specify the data. (a) Infer eta10 from the deuterium model. (b) Find the abundance predicted by the background value and the observed fractional excess; state what uncertainties are needed before judging a discrepancy.
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Question 10 - Solution Independent abundance measurements test a shared cosmic baryon density η10 D/H (a) Method and calculation 3.0 2.5 = (6/η10)1.6 ⇒η10 = 6(2.5/3.0)1/1.6. η10 ≃5.354 . (b) Interpretation and further calculation (D/H)background = 2.5 × 10−5, Dobs −Dpred Dpred = .20 . z = Dobs −Dpred √ σ2 obs + σ2 pred for independent errors. Physical check A difference of central values alone is not a statistical rejection. Nuclear rates, measurement errors and the cosmological model enter the comparison.

Question 10

Independent abundance measurements test a shared cosmic baryon density

In an illustrative nucleosynthesis model, deuterium abundance is D/H=2.5×10−5(6/η10)1.6D/H=2.5\times10^{-5}(6/\eta_{10})^{1.6}, where η10=1010η\eta_{10}=10^{10}\eta. An observation gives D/H=3.0×10−5D/H=3.0\times10^{-5}. An independent background fit gives η10=6.0\eta_{10}=6.0.

Diagram shown in the original SVG worksheet.

  1. Infer eta10 from the deuterium model.

  2. Find the abundance predicted by the background value and the observed fractional excess; state what uncertainties are needed before judging a discrepancy.

Question 10 - Solution

Independent abundance measurements test a shared cosmic baryon density

Diagram shown in the original SVG worksheet.

(a) Method and calculation

3.02.5=(6/η10)1.6⇒η10=6(2.5/3.0)1/1.6.\frac{3.0}{2.5}=(6/\eta_{10})^{1.6}\Rightarrow\eta_{10}=6(2.5/3.0)^{1/1.6}.η10≃5.354.\boxed{\eta_{10}\simeq5.354}.

(b) Interpretation and further calculation

(D/H)background=2.5×10−5,Dobs−DpredDpred=.20.\boxed{(D/H)_{\mathrm{background}}=2.5\times10^{-5},\quad\frac{D_{\mathrm{obs}}-D_{\mathrm{pred}}}{D_{\mathrm{pred}}}=.20}.z=Dobs−Dpredσobs2+σpred2for independent errors.z=\frac{D_{\mathrm{obs}}-D_{\mathrm{pred}}}{\sqrt{\sigma_{\mathrm{obs}}^2+\sigma_{\mathrm{pred}}^2}}\quad\text{for independent errors}.

Physical check

A difference of central values alone is not a statistical rejection. Nuclear rates, measurement errors and the cosmological model enter the comparison.