The Big Bang — Question 5

Section 44-13 · Physics pages 7540–7541

Question 5 Helium abundance follows from counting the surviving neutrons Immediately before nucleosynthesis, let n/p=1/7. Assume all neutrons enter helium-4, each nucleus using two neutrons and two protons. Ignore binding-mass corrections and other nuclei. p p n n 4He Schematic; labels, not drawing lengths, specify the data. (a) Derive the helium baryon mass fraction in terms of r=n/p and evaluate it. (b) Find the helium-to-hydrogen number ratio and the fraction of initial protons incorporated into helium.
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Question 5 - Solution Helium abundance follows from counting the surviving neutrons p p n n 4He (a) Method and calculation NHe = n/2, Y = 4NHe n + p = 2r 1 + r = .25 . NH = p −n because helium consumes n protons. (b) Interpretation and further calculation NHe/NH = r 2(1 −r) = 1 12 = .0833333 . Np,He/p = n/p = 1/7 . Physical check Helium is about one quarter by mass in this model but about one helium nucleus per twelve hydrogen nuclei; mass and number fractions differ.

Question 5

Helium abundance follows from counting the surviving neutrons

Immediately before nucleosynthesis, let n/p=1/7. Assume all neutrons enter helium-4, each nucleus using two neutrons and two protons. Ignore binding-mass corrections and other nuclei.

Diagram shown in the original SVG worksheet.

  1. Derive the helium baryon mass fraction in terms of r=n/p and evaluate it.

  2. Find the helium-to-hydrogen number ratio and the fraction of initial protons incorporated into helium.

Question 5 - Solution

Helium abundance follows from counting the surviving neutrons

Diagram shown in the original SVG worksheet.

(a) Method and calculation

NHe=n/2,Y=4NHen+p=2r1+r=.25.N_{\mathrm{He}}=n/2,\quad Y=\frac{4N_{\mathrm{He}}}{n+p}=\boxed{\frac{2r}{1+r}=.25}.NH=p−nbecause helium consumes n protons.N_H=p-n\quad\text{because helium consumes }n\text{ protons}.

(b) Interpretation and further calculation

NHe/NH=r2(1−r)=112=.0833333.\boxed{N_{\mathrm{He}}/N_H=\frac{r}{2(1-r)}=\frac1{12}=.0833333}.Np,He/p=n/p=1/7.\boxed{N_{p,\mathrm{He}}/p=n/p=1/7}.

Physical check

Helium is about one quarter by mass in this model but about one helium nucleus per twelve hydrogen nuclei; mass and number fractions differ.