Dark Matter — Question 9

Section 44-12 · Physics pages 7528–7529

Question 9 A direct-detection rate depends on both particle mass and cross section Assume local dark-matter rest-energy density .30 GeV/cm3, particle rest energy 100 GeV and speed 2.0 × 107 cm/s. A detector has 1028 targets and effective scattering cross section 10−40 cm2 per target; ignore thresholds. χ recoil Schematic; labels, not drawing lengths, specify the data. (a) Find number density, flux and ideal event rate. (b) Find expected events in one year of 3.156 × 107 s, and how the rate changes if particle mass doubles at fixed density, speed and cross section.
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Question 9 - Solution A direct-detection rate depends on both particle mass and cross section χ recoil (a) Method and calculation nχ = .30/100 = .0030 cm−3, Φ = nχv = 6.0 × 104 cm−2s−1 . R = NT σΦ = 6.0 × 10−8 s−1 . (b) Interpretation and further calculation µ = Rt = 1.8936 events/year . R ∝nχ = ρχ/mχ ⇒R′ = R/2 . Physical check The effective cross section and fixed-speed model are supplied assumptions. Real recoil spectra require velocity distributions, nuclear response and detector acceptance.

Question 9

A direct-detection rate depends on both particle mass and cross section

Assume local dark-matter rest-energy density .30 GeV/cm3^3, particle rest energy 100 GeV and speed 2.0×1072.0\times10^7 cm/s. A detector has 102810^{28} targets and effective scattering cross section 10−4010^{-40} cm2^2 per target; ignore thresholds.

Diagram shown in the original SVG worksheet.

  1. Find number density, flux and ideal event rate.

  2. Find expected events in one year of 3.156×1073.156\times10^7 s, and how the rate changes if particle mass doubles at fixed density, speed and cross section.

Question 9 - Solution

A direct-detection rate depends on both particle mass and cross section

Diagram shown in the original SVG worksheet.

(a) Method and calculation

nχ=.30/100=.0030cm−3,Φ=nχv=6.0×104cm−2s−1.\boxed{n_\chi=.30/100=.0030\ {\mathrm{cm^{-3}}},\quad\Phi=n_\chi v=6.0\times10^4\ {\mathrm{cm^{-2}s^{-1}}}}.R=NTσΦ=6.0×10−8s−1.\boxed{R=N_T\sigma\Phi=6.0\times10^{-8}\ {\mathrm{s^{-1}}}}.

(b) Interpretation and further calculation

μ=Rt=1.8936events/year.\boxed{\mu=Rt=1.8936\ {\mathrm{events/year}}}.R∝nχ=ρχ/mχ⇒R′=R/2.R\propto n_\chi=\rho_\chi/m_\chi\Rightarrow\boxed{R^\prime=R/2}.

Physical check

The effective cross section and fixed-speed model are supplied assumptions. Real recoil spectra require velocity distributions, nuclear response and detector acceptance.