Dark Matter — Question 3

Section 44-12 · Physics pages 7516–7517

Question 3 Subtracting the luminous contribution requires subtracting squared speeds At a given radius, a spherical toy model predicts luminous-matter circular speed 120 km/s while the observed speed is 200 km/s. Independent gravitational potentials add, so v2 total = v2 b + v2 h. r vc Schematic; labels, not drawing lengths, specify the data. (a) Find the halo circular-speed contribution. (b) Find the luminous and halo fractions of enclosed dynamical mass under the spherical assumption.
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Question 3 - Solution Subtracting the luminous contribution requires subtracting squared speeds r vc (a) Method and calculation v2 h = 2002 −1202 = 25600 (km/s)2. vh = 160 km/s . (b) Interpretation and further calculation fb = Mb/Mtotal = v2 b/v2 total = .36 . fh = 1 −.36 = .64 . Physical check Subtracting speeds directly would give 80 km/s and an incorrect mass decomposition. The result depends on the adopted luminous-mass model.

Question 3

Subtracting the luminous contribution requires subtracting squared speeds

At a given radius, a spherical toy model predicts luminous-matter circular speed 120 km/s while the observed speed is 200 km/s. Independent gravitational potentials add, so vtotal2=vb2+vh2v_{\mathrm{total}}^2=v_b^2+v_h^2.

Diagram shown in the original SVG worksheet.

  1. Find the halo circular-speed contribution.

  2. Find the luminous and halo fractions of enclosed dynamical mass under the spherical assumption.

Question 3 - Solution

Subtracting the luminous contribution requires subtracting squared speeds

Diagram shown in the original SVG worksheet.

(a) Method and calculation

vh2=2002−1202=25600(km/s)2.v_h^2=200^2-120^2=25600\ ({\mathrm{km/s}})^2.vh=160km/s.\boxed{v_h=160\ {\mathrm{km/s}}}.

(b) Interpretation and further calculation

fb=Mb/Mtotal=vb2/vtotal2=.36.\boxed{f_b=M_b/M_{\mathrm{total}}=v_b^2/v_{\mathrm{total}}^2=.36}.fh=1−.36=.64.\boxed{f_h=1-.36=.64}.

Physical check

Subtracting speeds directly would give 80 km/s and an incorrect mass decomposition. The result depends on the adopted luminous-mass model.