The Universe Is Expanding — Question 5

Section 44-10 · Physics pages 7480–7481

Question 5 Cosmological time dilation stretches a transient light curve A transient at z=.80 rises for 12 days in its rest frame and emits photons of rest-frame wavelength 400 nm. Neglect peculiar motion. t emitted and stretched pulses Schematic; labels, not drawing lengths, specify the data. (a) Find the observed rise time and wavelength. (b) If one pulse emitted N photons of energy E each over rest-frame duration t, find the observed energy-arrival rate factor due solely to redshift and time dilation, excluding geometric dilution.
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Question 5 - Solution Cosmological time dilation stretches a transient light curve t emitted and stretched pulses (a) Method and calculation to = (1 + z)te = 1.8(12) = 21.6 d . λo = 1.8(400) = 720 nm . (b) Interpretation and further calculation Eo = Ee/(1 + z), to = (1 + z)te. NEo/to NEe/te = (1 + z)−2 = .308642 . Physical check Each photon loses an energy factor and their arrival rate gains a separate time factor; luminosity distance incorporates these effects.

Question 5

Cosmological time dilation stretches a transient light curve

A transient at z=.80 rises for 12 days in its rest frame and emits photons of rest-frame wavelength 400 nm. Neglect peculiar motion.

Diagram shown in the original SVG worksheet.

  1. Find the observed rise time and wavelength.

  2. If one pulse emitted N photons of energy E each over rest-frame duration t, find the observed energy-arrival rate factor due solely to redshift and time dilation, excluding geometric dilution.

Question 5 - Solution

Cosmological time dilation stretches a transient light curve

Diagram shown in the original SVG worksheet.

(a) Method and calculation

to=(1+z)te=1.8(12)=21.6d.\boxed{t_o=(1+z)t_e=1.8(12)=21.6\ {\mathrm{d}}}.λo=1.8(400)=720nm.\boxed{\lambda_o=1.8(400)=720\ {\mathrm{nm}}}.

(b) Interpretation and further calculation

Eo=Ee/(1+z),to=(1+z)te.E_o=E_e/(1+z),\quad t_o=(1+z)t_e.NEo/toNEe/te=(1+z)−2=.308642.\boxed{\frac{NE_o/t_o}{NE_e/t_e}=(1+z)^{-2}=.308642}.

Physical check

Each photon loses an energy factor and their arrival rate gains a separate time factor; luminosity distance incorporates these effects.