Particles, Particles, Particles — Question 7

Section 44-1 · Physics pages 7304–7305

Question 7 Event yields determine a cross section only after efficiency correction A collision sample has integrated luminosity L = 50.0 pb−1. A selected channel has 500 candidates, estimated background 100, and signal efficiency .400. Treat luminosity, efficiency and background as exact for this exercise. candidates subtract background signal Schematic; labels, not drawing lengths, specify the data. (a) Infer the channel cross section. (b) Using Poisson uncertainty on the candidate count, estimate its standard uncertainty and the luminosity needed to halve that relative error at fixed rates.
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Question 7 - Solution Event yields determine a cross section only after efficiency correction candidates subtract background signal (a) Method and calculation Ns = Nobs −Nb = 400, Ns = ϵLσ. σ = 400/[.400(50.0)] = 20.0 pb . (b) Interpretation and further calculation σσ = √ 500/[.400(50.0)] = 1.11803 pb . σσ/σ ∝L−1/2 ⇒L′ = 4L = 200 pb−1 . Physical check Background uncertainty would increase the error. An event count is not a cross section until acceptance, efficiency and exposure are accounted for.

Question 7

Event yields determine a cross section only after efficiency correction

A collision sample has integrated luminosity ℒ=50.0pb−1\mathcal L=50.0\,\mathrm{pb^{-1}}. A selected channel has 500 candidates, estimated background 100, and signal efficiency .400. Treat luminosity, efficiency and background as exact for this exercise.

Diagram shown in the original SVG worksheet.

  1. Infer the channel cross section.

  2. Using Poisson uncertainty on the candidate count, estimate its standard uncertainty and the luminosity needed to halve that relative error at fixed rates.

Question 7 - Solution

Event yields determine a cross section only after efficiency correction

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Ns=Nobs−Nb=400,Ns=ϵℒσ.N_s=N_{\mathrm{obs}}-N_b=400,\quad N_s=\epsilon\mathcal L\sigma.σ=400/[.400(50.0)]=20.0pb.\boxed{\sigma=400/[.400(50.0)]=20.0\,\mathrm{pb}}.

(b) Interpretation and further calculation

σσ=500/[.400(50.0)]=1.11803pb.\boxed{\sigma_\sigma=\sqrt{500}/[.400(50.0)]=1.11803\,\mathrm{pb}}.σσ/σ∝ℒ−1/2⇒ℒ′=4ℒ=200pb−1.\sigma_\sigma/\sigma\propto\mathcal L^{-1/2}\Rightarrow\boxed{\mathcal L\prime=4\mathcal L=200\,\mathrm{pb^{-1}}}.

Physical check

Background uncertainty would increase the error. An event count is not a cross section until acceptance, efficiency and exposure are accounted for.