Particles, Particles, Particles — Question 4

Section 44-1 · Physics pages 7298–7299

Question 4 A decay-length distribution reveals the particle proper lifetime A particle beam has pc = 3.00 GeV and mc2 = 1.00 GeV. The mean measured decay length is 9.00 cm. Use c=3.00 × 108 m/s and an exponential proper-time law. production L Schematic; labels, not drawing lengths, specify the data. (a) Infer the proper mean lifetime. (b) Find the fraction decaying between 3.00 cm and 12.0 cm from production.
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Question 4 - Solution A decay-length distribution reveals the particle proper lifetime production L (a) Method and calculation ¯L = βγcτ = pc mc2 cτ = 3cτ. τ = .0900/(3c) = 1.00 × 10−10 s . (b) Interpretation and further calculation P(a < L < b) = e−a/¯L −e−b/¯L. P = e−1/3 −e−4/3 = .452934 . Physical check The mean flight distance depends on momentum. A broad momentum spectrum must be handled event by event rather than assigned a single boost.

Question 4

A decay-length distribution reveals the particle proper lifetime

A particle beam has pc=3.00pc=3.00 GeV and mc2=1.00mc^2=1.00 GeV. The mean measured decay length is 9.00 cm. Use c=3.00×1083.00\times10^8 m/s and an exponential proper-time law.

Diagram shown in the original SVG worksheet.

  1. Infer the proper mean lifetime.

  2. Find the fraction decaying between 3.00 cm and 12.0 cm from production.

Question 4 - Solution

A decay-length distribution reveals the particle proper lifetime

Diagram shown in the original SVG worksheet.

(a) Method and calculation

L‾=βγcτ=pcmc2cτ=3cτ.\bar L=\beta\gamma c\tau=\frac{pc}{mc^2}c\tau=3c\tau.τ=.0900/(3c)=1.00×10−10s.\boxed{\tau=.0900/(3c)=1.00\times10^{-10}\,\mathrm s}.

(b) Interpretation and further calculation

P(a<L<b)=e−a/L‾−e−b/L‾.P(a<L<b)=e^{-a/\bar L}-e^{-b/\bar L}.P=e−1/3−e−4/3=.452934.\boxed{P=e^{-1/3}-e^{-4/3}=.452934}.

Physical check

The mean flight distance depends on momentum. A broad momentum spectrum must be handled event by event rather than assigned a single boost.