Thermonuclear Fusion in the Sun and Other Stars — Question 9

Section 43-6 · Physics pages 7268–7269

Question 9 Hydrostatic pressure supplies a central temperature scale For a uniform-density, fully ionized hydrogen star, use Pc = 3GM2/(8πR4), ρ = 3M/(4πR3) and P = 2ρkT/mp. Take M = 2.00 × 1030 kg, R = 7.00 × 108 m, G = 6.67 × 10−11 SI, mp = 1.67 × 10−27 kg and k = 1.38 × 10−23 J/K. core L Schematic; labels, not drawing lengths, specify the data. (a) Derive a central temperature expression and evaluate it. (b) At fixed mass, infer how this temperature scale changes if the radius contracts by 10 percent.
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Question 9 - Solution Hydrostatic pressure supplies a central temperature scale core L (a) Method and calculation Tc = mp 2k Pc ρ = mp 2k GM 2R . Tc = GMmp 4Rk = 5.76548 × 106 K . (b) Interpretation and further calculation Tc ∝R−1 ⇒Tc′/Tc = 1/.900 = 1.11111 . ∆Tc/Tc = .11111 an 11.111 percent increase. Physical check The factor two counts ions and electrons. Uniform density is crude; realistic profiles, composition and radiation pressure change central temperature.

Question 9

Hydrostatic pressure supplies a central temperature scale

For a uniform-density, fully ionized hydrogen star, use Pc=3GM2/(8πR4)P_c=3GM^2/(8\pi R^4), ρ=3M/(4πR3)\rho=3M/(4\pi R^3) and P=2ρkT/mpP=2\rho kT/m_p. Take M=2.00×1030M=2.00\times10^{30} kg, R=7.00×108R=7.00\times10^8 m, G=6.67×10−11G=6.67\times10^{-11} SI, mp=1.67×10−27m_p=1.67\times10^{-27} kg and k=1.38×10−23k=1.38\times10^{-23} J/K.

Diagram shown in the original SVG worksheet.

  1. Derive a central temperature expression and evaluate it.

  2. At fixed mass, infer how this temperature scale changes if the radius contracts by 10 percent.

Question 9 - Solution

Hydrostatic pressure supplies a central temperature scale

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Tc=mp2kPcρ=mp2kGM2R.T_c=\frac{m_p}{2k}\frac{P_c}{\rho}=\frac{m_p}{2k}\frac{GM}{2R}.Tc=GMmp4Rk=5.76548×106K.\boxed{T_c=\frac{GMm_p}{4Rk}=5.76548\times10^6\,\mathrm K}.

(b) Interpretation and further calculation

Tc∝R−1⇒Tc′/Tc=1/.900=1.11111.T_c\propto R^{-1}\Rightarrow\boxed{T_c\prime/T_c=1/.900=1.11111}.ΔTc/Tc=.11111an 11.111 percent increase.\boxed{\Delta T_c/T_c=.11111}\quad\text{an 11.111 percent increase}.

Physical check

The factor two counts ions and electrons. Uniform density is crude; realistic profiles, composition and radiation pressure change central temperature.