Thermonuclear Fusion in the Sun and Other Stars — Question 1

Section 43-6 · Physics pages 7252–7253

Question 1 Adding proton-proton-chain steps reveals the net stellar reaction Use two copies each of p + p →d + e+ + νe and d + p →3He + γ, followed by 3He + 3He →4He + 2p. p + p d 3He 4He after two branches Schematic; labels, not drawing lengths, specify the data. (a) Cancel intermediate nuclei to obtain the net nuclear reaction, and check charge and lepton number. (b) Include annihilation of both positrons with ambient electrons and write the resulting net matter transformation.
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Question 1 - Solution Adding proton-proton-chain steps reveals the net stellar reaction p + p d 3He 4He after two branches (a) Method and calculation 6p →4He + 2p + 2e+ + 2νe + photons. 4p →4He + 2e+ + 2νe + energy ; Q : 4 = 2 + 2, L : 0 = −2 + 2. (b) Interpretation and further calculation 2e+ + 2e−→annihilation photons. 4p + 2e−→4He + 2νe + energy ; L : 2 = 2. Physical check Four protons are consumed per completed chain, although six participate in the written intermediate steps. Photons and neutrinos carry energy away from the reaction sites.

Question 1

Adding proton-proton-chain steps reveals the net stellar reaction

Use two copies each of p+p→d+e++νep+p\to d+e^++\nu_e and d+p→3He+γd+p\to{}^3\mathrm{He}+\gamma, followed by 3He+3He→4He+2p{}^3\mathrm{He}+{}^3\mathrm{He}\to{}^4\mathrm{He}+2p.

Diagram shown in the original SVG worksheet.

  1. Cancel intermediate nuclei to obtain the net nuclear reaction, and check charge and lepton number.

  2. Include annihilation of both positrons with ambient electrons and write the resulting net matter transformation.

Question 1 - Solution

Adding proton-proton-chain steps reveals the net stellar reaction

Diagram shown in the original SVG worksheet.

(a) Method and calculation

6p→4He+2p+2e++2νe+photons.6p\to{}^4\mathrm{He}+2p+2e^++2\nu_e+\text{photons}.4p→4He+2e++2νe+energy;Q:4=2+2,L:0=−2+2.\boxed{4p\to{}^4\mathrm{He}+2e^++2\nu_e+\text{energy}};\quad Q:\ 4=2+2,\ L:\ 0=-2+2.

(b) Interpretation and further calculation

2e++2e−→annihilation photons.2e^++2e^-\to\text{annihilation photons}.4p+2e−→4He+2νe+energy;L:2=2.\boxed{4p+2e^-\to{}^4\mathrm{He}+2\nu_e+\text{energy}};\quad L:\ 2=2.

Physical check

Four protons are consumed per completed chain, although six participate in the written intermediate steps. Photons and neutrinos carry energy away from the reaction sites.