The Nuclear Reactor — Question 1

Section 43-3 · Physics pages 7192–7193

Question 1 A nuclear power station balances electrical output and rejected heat A station delivers 900 MW of electrical power at thermal efficiency .360. Treat all other thermal energy as rejected to the environment. thermal source engine Pe Pwaste Schematic; labels, not drawing lengths, specify the data. (a) Calculate thermal input power and waste heat rate. (b) At the same electrical output, an improved efficiency of .400 is proposed. Find the reduction in thermal input and waste heat.
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Question 1 - Solution A nuclear power station balances electrical output and rejected heat thermal source engine Pe Pwaste (a) Method and calculation η = Pe/Pth ⇒Pth = 900/.360 = 2500 MW . Pwaste = Pth −Pe = 1600 MW . (b) Interpretation and further calculation Pth′ = 900/.400 = 2250 MW, Pwaste′ = 1350 MW . ∆Pth = ∆Pwaste = −250 MW . Physical check Greater conversion efficiency reduces rejected heat at fixed electrical output. Thermal power and electrical power must not be interchanged.

Question 1

A nuclear power station balances electrical output and rejected heat

A station delivers 900 MW of electrical power at thermal efficiency .360. Treat all other thermal energy as rejected to the environment.

Diagram shown in the original SVG worksheet.

  1. Calculate thermal input power and waste heat rate.

  2. At the same electrical output, an improved efficiency of .400 is proposed. Find the reduction in thermal input and waste heat.

Question 1 - Solution

A nuclear power station balances electrical output and rejected heat

Diagram shown in the original SVG worksheet.

(a) Method and calculation

η=Pe/Pth⇒Pth=900/.360=2500MW.\eta=P_e/P_{\mathrm{th}}\Rightarrow\boxed{P_{\mathrm{th}}=900/.360=2500\,\mathrm{MW}}.Pwaste=Pth−Pe=1600MW.\boxed{P_{\mathrm{waste}}=P_{\mathrm{th}}-P_e=1600\,\mathrm{MW}}.

(b) Interpretation and further calculation

Pth′=900/.400=2250MW,Pwaste′=1350MW.\boxed{P_{\mathrm{th}}\prime=900/.400=2250\,\mathrm{MW},\quad P_{\mathrm{waste}}\prime=1350\,\mathrm{MW}}.ΔPth=ΔPwaste=−250MW.\boxed{\Delta P_{\mathrm{th}}=\Delta P_{\mathrm{waste}}=-250\,\mathrm{MW}}.

Physical check

Greater conversion efficiency reduces rejected heat at fixed electrical output. Thermal power and electrical power must not be interchanged.