Nuclear Models — Question 8

Section 42-8 · Physics pages 7146–7147

Question 8 Spin-orbit coupling splits a nuclear orbital into two multiplets A nucleon with ℓ= 2 and s = 1/2 has interaction Hls = κ L · S/ℏ2, with κ = −1.00 MeV. Use L · S = 1 2[J2 −L2 −S2]. j = 5/2 j = 3/2 ∆E Schematic; labels, not drawing lengths, specify the data. (a) Calculate the energy shifts for j = 5/2 and j = 3/2. (b) Find their separation and check that their total capacity equals the unsplit orbital capacity.
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Question 8 - Solution Spin-orbit coupling splits a nuclear orbital into two multiplets j = 5/2 j = 3/2 ∆E (a) Method and calculation ∆Ej = κ 2[j(j + 1) −ℓ(ℓ+ 1) −s(s + 1)]. ∆E5/2 = κ = −1.00 MeV, ∆E3/2 = −3κ/2 = +1.50 MeV . (b) Interpretation and further calculation ∆E3/2 −∆E5/2 = 2.50 MeV . (2 × 5/2 + 1) + (2 × 3/2 + 1) = 6 + 4 = 10 = 2(2ℓ+ 1) . Physical check For the negative coupling used here, the aligned j=ell+1/2 multiplet is lower. Splitting reorganizes energies without changing the total number of states.

Question 8

Spin-orbit coupling splits a nuclear orbital into two multiplets

A nucleon with ℓ=2\ell=2 and s=1/2s=1/2 has interaction Hls=κ𝑳⋅𝑺/ℏ2H_{ls}=\kappa\,\mathbf L\cdot\mathbf S/\hbar^2, with κ=−1.00MeV\kappa=-1.00\,\mathrm{MeV}. Use 𝑳⋅𝑺=12[J2−L2−S2]\mathbf L\cdot\mathbf S=\tfrac12[J^2-L^2-S^2].

Diagram shown in the original SVG worksheet.

  1. Calculate the energy shifts for j=5/2j=5/2 and j=3/2j=3/2.

  2. Find their separation and check that their total capacity equals the unsplit orbital capacity.

Question 8 - Solution

Spin-orbit coupling splits a nuclear orbital into two multiplets

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ΔEj=κ2[j(j+1)−ℓ(ℓ+1)−s(s+1)].\Delta E_j=\frac\kappa2[j(j+1)-\ell(\ell+1)-s(s+1)].ΔE5/2=κ=−1.00MeV,ΔE3/2=−3κ/2=+1.50MeV.\boxed{\Delta E_{5/2}=\kappa=-1.00\,\mathrm{MeV},\quad\Delta E_{3/2}=-3\kappa/2=+1.50\,\mathrm{MeV}}.

(b) Interpretation and further calculation

ΔE3/2−ΔE5/2=2.50MeV.\boxed{\Delta E_{3/2}-\Delta E_{5/2}=2.50\,\mathrm{MeV}}.(2×5/2+1)+(2×3/2+1)=6+4=10=2(2ℓ+1).\boxed{(2\times5/2+1)+(2\times3/2+1)=6+4=10=2(2\ell+1)}.

Physical check

For the negative coupling used here, the aligned j=ell+1/2 multiplet is lower. Splitting reorganizes energies without changing the total number of states.