Radioactive Dating — Question 9

Section 42-6 · Physics pages 7108–7109

Question 9 A reservoir offset changes the fraction present at closure An organism begins with carbon-14 fraction .800 relative to the reference atmosphere because of its reservoir. At measurement the fraction is .200. Assume closed-system decay with half-life 5730 y and no later contamination. t f Schematic; labels, not drawing lengths, specify the data. (a) Calculate the elapsed time since closure using the correct initial fraction. (b) Find the apparent age assuming an initial fraction of 1 and derive the reservoir age offset.
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Question 9 - Solution A reservoir offset changes the fraction present at closure t f (a) Method and calculation f = f0e−λt ⇒t = λ−1 ln(f0/f) . t = 5730 log2(.800/.200) = 11460 y . (b) Interpretation and further calculation tapp = 5730 log2(1/.200) = 13305 y . ∆t = tapp −t = 5730 log2(1/.800) = 1845 y . Physical check The offset reflects the initial isotope ratio, not an additional period after the organism stopped exchanging carbon. A real reservoir correction may vary in space and time.

Question 9

A reservoir offset changes the fraction present at closure

An organism begins with carbon-14 fraction .800 relative to the reference atmosphere because of its reservoir. At measurement the fraction is .200. Assume closed-system decay with half-life 5730 y and no later contamination.

Diagram shown in the original SVG worksheet.

  1. Calculate the elapsed time since closure using the correct initial fraction.

  2. Find the apparent age assuming an initial fraction of 1 and derive the reservoir age offset.

Question 9 - Solution

A reservoir offset changes the fraction present at closure

Diagram shown in the original SVG worksheet.

(a) Method and calculation

f=f0e−λt⇒t=λ−1ln⁡(f0/f).f=f_0e^{-\lambda t}\Rightarrow\boxed{t=\lambda^{-1}\ln(f_0/f)}.t=5730log⁡2(.800/.200)=11460y.\boxed{t=5730\log_2(.800/.200)=11460\,\mathrm y}.

(b) Interpretation and further calculation

tapp=5730log⁡2(1/.200)=13305y.\boxed{t_{\mathrm{app}}=5730\log_2(1/.200)=13305\,\mathrm y}.Δt=tapp−t=5730log⁡2(1/.800)=1845y.\boxed{\Delta t=t_{\mathrm{app}}-t=5730\log_2(1/.800)=1845\,\mathrm y}.

Physical check

The offset reflects the initial isotope ratio, not an additional period after the organism stopped exchanging carbon. A real reservoir correction may vary in space and time.