Radioactive Dating — Question 1

Section 42-6 · Physics pages 7092–7093

Question 1 A carbon activity ratio gives an ideal closed-system age A preserved organic sample has carbon-specific activity 3.00 counts per minute per gram under a fixed counting setup. A modern reference measured with identical efficiency has 12.0 counts per minute per gram. Use carbon-14 half-life 5730 y, equal initial isotope ratios and no contamination. t/T1/2 f Schematic; labels, not drawing lengths, specify the data. (a) Derive the age from the activity ratio. (b) Predict the sample-to-reference ratio after a further 5730 y and explain why total sample mass is not needed.
Show solutionHide solution
Question 1 - Solution A carbon activity ratio gives an ideal closed-system age t/T1/2 f (a) Method and calculation f = A/A0 = e−λt ⇒t = T1/2 ln 2 ln(A0/A) . f = 3.00/12.0 = .250, t = 2(5730) = 11460 y . (b) Interpretation and further calculation f′ = f/2 = .125 . Aspecific = λN14/mC ⇒carbon-mass normalization removes sample-size dependence . Physical check This is an ideal decay-model age. Calendar dating requires calibration of past atmospheric isotope ratios and appropriate reservoir corrections.

Question 1

A carbon activity ratio gives an ideal closed-system age

A preserved organic sample has carbon-specific activity 3.00 counts per minute per gram under a fixed counting setup. A modern reference measured with identical efficiency has 12.0 counts per minute per gram. Use carbon-14 half-life 5730 y, equal initial isotope ratios and no contamination.

Diagram shown in the original SVG worksheet.

  1. Derive the age from the activity ratio.

  2. Predict the sample-to-reference ratio after a further 5730 y and explain why total sample mass is not needed.

Question 1 - Solution

A carbon activity ratio gives an ideal closed-system age

Diagram shown in the original SVG worksheet.

(a) Method and calculation

f=𝒜/𝒜0=e−λt⇒t=T1/2ln⁡2ln⁡(𝒜0/𝒜).f=\mathcal A/\mathcal A_0=e^{-\lambda t}\Rightarrow\boxed{t=\frac{T_{1/2}}{\ln2}\ln(\mathcal A_0/\mathcal A)}.f=3.00/12.0=.250,t=2(5730)=11460y.\boxed{f=3.00/12.0=.250,\quad t=2(5730)=11460\,\mathrm y}.

(b) Interpretation and further calculation

f′=f/2=.125.\boxed{f\prime=f/2=.125}.𝒜specific=λN14/mC⇒carbon-mass normalization removes sample-size dependence.\mathcal A_{\mathrm{specific}}=\lambda N_{14}/m_C\Rightarrow\boxed{\text{carbon-mass normalization removes sample-size dependence}}.

Physical check

This is an ideal decay-model age. Calendar dating requires calibration of past atmospheric isotope ratios and appropriate reservoir corrections.