Radioactive Decay — Question 7

Section 42-3 · Physics pages 7044–7045

Question 7 Constant production competes with radioactive loss A process produces a radionuclide at constant rate P from t=0, starting with N=0. The nuclei decay with constant lambda. Production is stopped at tp = 2T1/2. t A tp Schematic; labels, not drawing lengths, specify the data. (a) Solve for N(t) while production continues and identify saturation activity. (b) Find activity immediately when production stops and one half-life later, in units of P.
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Question 7 - Solution Constant production competes with radioactive loss t A tp (a) Method and calculation ˙N = P −λN ⇒N(t) = P λ (1 −e−λt) . A(t) = P(1 −e−λt), Asat = P . (b) Interpretation and further calculation A(tp) = P(1 −1/4) = 3P/4 . A(tp + T1/2) = (3P/4)(1/2) = 3P/8 . Physical check At saturation, production and decay rates balance although individual nuclei continue to be replaced. After production stops, the ordinary decay law applies.

Question 7

Constant production competes with radioactive loss

A process produces a radionuclide at constant rate P from t=0, starting with N=0. The nuclei decay with constant lambda. Production is stopped at tp=2T1/2t_p=2T_{1/2}.

Diagram shown in the original SVG worksheet.

  1. Solve for N(t) while production continues and identify saturation activity.

  2. Find activity immediately when production stops and one half-life later, in units of P.

Question 7 - Solution

Constant production competes with radioactive loss

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Ṅ=P−λN⇒N(t)=Pλ(1−e−λt).\dot N=P-\lambda N\Rightarrow\boxed{N(t)=\frac P\lambda(1-e^{-\lambda t})}.𝒜(t)=P(1−e−λt),𝒜sat=P.\boxed{\mathcal A(t)=P(1-e^{-\lambda t}),\quad\mathcal A_{\mathrm{sat}}=P}.

(b) Interpretation and further calculation

𝒜(tp)=P(1−1/4)=3P/4.\boxed{\mathcal A(t_p)=P(1-1/4)=3P/4}.𝒜(tp+T1/2)=(3P/4)(1/2)=3P/8.\boxed{\mathcal A(t_p+T_{1/2})=(3P/4)(1/2)=3P/8}.

Physical check

At saturation, production and decay rates balance although individual nuclei continue to be replaced. After production stops, the ordinary decay law applies.