Radioactive Decay — Question 3

Section 42-3 · Physics pages 7036–7037

Question 3 Activity and sample mass are connected through the decay constant A pure radionuclide has molar mass M = 100 g/mol and half-life 10.0 days. Its initial mass is 1.00 µg. Use NA = 6.022 × 1023 mol−1 and 86400 s per day. parent daughter emission Schematic; labels, not drawing lengths, specify the data. (a) Find the initial number of nuclei and activity in becquerels. (b) Find its activity and remaining mass after 30.0 days.
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Question 3 - Solution Activity and sample mass are connected through the decay constant parent daughter emission (a) Method and calculation N0 = (m/M)NA = (10−6/100)(6.022 × 1023) = 6.022 × 1015 . A0 = λN0 = ln 2 864000(6.022 × 1015) = 4.831 × 109 Bq . (b) Interpretation and further calculation 30.0 d = 3T1/2 ⇒A = A0/8 = 6.039 × 108 Bq . m = m0/8 = .125 µg . Physical check Activity measures decays per second, not energy released per decay. The mass specified is the remaining parent mass, excluding accumulated daughters.

Question 3

Activity and sample mass are connected through the decay constant

A pure radionuclide has molar mass M=100g/molM=100\,\mathrm{g/mol} and half-life 10.0 days. Its initial mass is 1.00μg1.00\,\mu\mathrm g. Use NA=6.022×1023mol−1N_A=6.022\times10^{23}\,\mathrm{mol^{-1}} and 86400 s per day.

Diagram shown in the original SVG worksheet.

  1. Find the initial number of nuclei and activity in becquerels.

  2. Find its activity and remaining mass after 30.0 days.

Question 3 - Solution

Activity and sample mass are connected through the decay constant

Diagram shown in the original SVG worksheet.

(a) Method and calculation

N0=(m/M)NA=(10−6/100)(6.022×1023)=6.022×1015.\boxed{N_0=(m/M)N_A=(10^{-6}/100)(6.022\times10^{23})=6.022\times10^{15}}.𝒜0=λN0=ln⁡2864000(6.022×1015)=4.831×109Bq.\boxed{\mathcal A_0=\lambda N_0=\frac{\ln2}{864000}(6.022\times10^{15})=4.831\times10^9\,\mathrm{Bq}}.

(b) Interpretation and further calculation

30.0d=3T1/2⇒𝒜=𝒜0/8=6.039×108Bq.30.0\,\mathrm d=3T_{1/2}\Rightarrow\boxed{\mathcal A=\mathcal A_0/8=6.039\times10^8\,\mathrm{Bq}}.m=m0/8=.125μg.\boxed{m=m_0/8=.125\,\mu\mathrm g}.

Physical check

Activity measures decays per second, not energy released per decay. The mass specified is the remaining parent mass, excluding accumulated daughters.