Some Nuclear Properties — Question 8

Section 42-2 · Physics pages 7026–7027

Question 8 Mass uncertainty propagates directly into binding-energy uncertainty A nucleus has binding energy B = [ZmH + Nmn −M]c2. Treat mH and mn as exact for this exercise. Its measured atomic mass is M = (55.93494 ± .00002) u, with one-standard-deviation uncertainty. Use 1 u c2 = 931.5 MeV and A=56. M M ± σM Schematic; labels, not drawing lengths, specify the data. (a) Find the uncertainty in total binding energy and in binding energy per nucleon. (b) Two independent mass measurements each have uncertainty .00002 u. Find the uncertainty in a separation energy obtained from their difference.
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Question 8 - Solution Mass uncertainty propagates directly into binding-energy uncertainty M M ± σM (a) Method and calculation σB = c2σM = 931.5(.00002) = .01863 MeV . σB/A = .01863/56 = .0003327 MeV = .3327 keV . (b) Interpretation and further calculation σ∆M = √ σ2 M1 + σ2 M2 = √ 2(.00002) u. σS = √ 2(.01863) = .02635 MeV . Physical check Independent errors add in quadrature. Correlated mass calibrations can change the uncertainty of a difference and require a covariance term.

Question 8

Mass uncertainty propagates directly into binding-energy uncertainty

A nucleus has binding energy B=[ZmH+Nmn−M]c2B=[Zm_H+Nm_n-M]c^2. Treat mHm_H and mnm_n as exact for this exercise. Its measured atomic mass is M=(55.93494±.00002)uM=(55.93494\pm .00002)\,\mathrm u, with one-standard-deviation uncertainty. Use 1uc2=931.5MeV1\,\mathrm u\,c^2=931.5\,\mathrm{MeV} and A=56.

Diagram shown in the original SVG worksheet.

  1. Find the uncertainty in total binding energy and in binding energy per nucleon.

  2. Two independent mass measurements each have uncertainty .00002 u. Find the uncertainty in a separation energy obtained from their difference.

Question 8 - Solution

Mass uncertainty propagates directly into binding-energy uncertainty

Diagram shown in the original SVG worksheet.

(a) Method and calculation

σB=c2σM=931.5(.00002)=.01863MeV.\boxed{\sigma_B=c^2\sigma_M=931.5(.00002)=.01863\,\mathrm{MeV}}.σB/A=.01863/56=.0003327MeV=.3327keV.\boxed{\sigma_{B/A}=.01863/56=.0003327\,\mathrm{MeV}=.3327\,\mathrm{keV}}.

(b) Interpretation and further calculation

σΔM=σM12+σM22=2(.00002)u.\sigma_{\Delta M}=\sqrt{\sigma_{M_1}^2+\sigma_{M_2}^2}=\sqrt2(.00002)\,\mathrm u.σS=2(.01863)=.02635MeV.\boxed{\sigma_S=\sqrt2(.01863)=.02635\,\mathrm{MeV}}.

Physical check

Independent errors add in quadrature. Correlated mass calibrations can change the uncertainty of a difference and require a covariance term.