Some Nuclear Properties — Question 6

Section 42-2 · Physics pages 7022–7023

Question 6 Separation energy measures the cost of removing the last neutron Two isotopes of the same element have supplied atomic masses M(A) = 99.950000 u and M(A −1) = 98.945000 u. Use mn = 1.008665 u and 1 u c2 = 931.5 MeV. parent daughter n Schematic; labels, not drawing lengths, specify the data. (a) Find the one-neutron separation energy of isotope A. (b) If its total binding energy is 850 MeV, determine the binding energy of isotope A-1 and explain why the separation energy differs from B/A.
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Question 6 - Solution Separation energy measures the cost of removing the last neutron parent daughter n (a) Method and calculation AX →A−1X + n : Sn = [M(A −1) + mn −M(A)]c2 . Sn = .003665(931.5) = 3.414 MeV . (b) Interpretation and further calculation Sn = B(A) −B(A −1) ⇒B(A −1) = 850 −3.414 = 846.586 MeV . Sn is a finite difference of total binding energies, not their average per nucleon . Physical check The electron count is unchanged when a neutron is removed, so atomic masses are suitable. A positive separation energy means spontaneous neutron removal is energetically forbidden from the ground state.

Question 6

Separation energy measures the cost of removing the last neutron

Two isotopes of the same element have supplied atomic masses M(A)=99.950000uM(A)=99.950000\,\mathrm u and M(A−1)=98.945000uM(A-1)=98.945000\,\mathrm u. Use mn=1.008665um_n=1.008665\,\mathrm u and 1uc2=931.5MeV1\,\mathrm u\,c^2=931.5\,\mathrm{MeV}.

Diagram shown in the original SVG worksheet.

  1. Find the one-neutron separation energy of isotope A.

  2. If its total binding energy is 850 MeV, determine the binding energy of isotope A-1 and explain why the separation energy differs from B/A.

Question 6 - Solution

Separation energy measures the cost of removing the last neutron

Diagram shown in the original SVG worksheet.

(a) Method and calculation

AX→A−1X+n:Sn=[M(A−1)+mn−M(A)]c2.{}^AX\to{}^{A-1}X+n:\quad\boxed{S_n=[M(A-1)+m_n-M(A)]c^2}.Sn=.003665(931.5)=3.414MeV.\boxed{S_n=.003665(931.5)=3.414\,\mathrm{MeV}}.

(b) Interpretation and further calculation

Sn=B(A)−B(A−1)⇒B(A−1)=850−3.414=846.586MeV.S_n=B(A)-B(A-1)\Rightarrow\boxed{B(A-1)=850-3.414=846.586\,\mathrm{MeV}}.Sn is a finite difference of total binding energies, not their average per nucleon.\boxed{S_n\text{ is a finite difference of total binding energies, not their average per nucleon}}.

Physical check

The electron count is unchanged when a neutron is removed, so atomic masses are suitable. A positive separation energy means spontaneous neutron removal is energetically forbidden from the ground state.