Some Nuclear Properties — Question 1

Section 42-2 · Physics pages 7012–7013

Question 1 Isotope bookkeeping separates nuclear composition from ionic charge A nucleus is written 64 29X. Its ion carries net charge +2e. A second isotope has the same proton number but three additional neutrons. 29p + 35n 27 bound electrons Schematic; labels, not drawing lengths, specify the data. (a) Find the numbers of protons, neutrons and bound electrons in the first ion. (b) Write the second isotope in nuclear notation and find the fractional change in nucleon count.
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Question 1 - Solution Isotope bookkeeping separates nuclear composition from ionic charge 29p + 35n 27 bound electrons (a) Method and calculation Z = 29, N = A −Z = 64 −29 = 35 . Q/e = Z −Ne = 2 ⇒Ne = 27 . (b) Interpretation and further calculation N′ = 38, A′ = 29 + 38 = 67 ⇒ 67 29X . (A′ −A)/A = 3/64 = .046875 = 4.69% . Physical check Ionization changes the electron count but neither Z nor A. Isotopes share a proton number while differing in neutron number.

Question 1

Isotope bookkeeping separates nuclear composition from ionic charge

A nucleus is written 2964X{}^{64}_{29}X. Its ion carries net charge +2e+2e. A second isotope has the same proton number but three additional neutrons.

Diagram shown in the original SVG worksheet.

  1. Find the numbers of protons, neutrons and bound electrons in the first ion.

  2. Write the second isotope in nuclear notation and find the fractional change in nucleon count.

Question 1 - Solution

Isotope bookkeeping separates nuclear composition from ionic charge

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Z=29,N=A−Z=64−29=35.\boxed{Z=29,\quad N=A-Z=64-29=35}.Q/e=Z−Ne=2⇒Ne=27.Q/e=Z-N_e=2\Rightarrow\boxed{N_e=27}.

(b) Interpretation and further calculation

N′=38,A′=29+38=67⇒2967X.N\prime=38,\quad A\prime=29+38=67\Rightarrow\boxed{{}^{67}_{29}X}.(A′−A)/A=3/64=.046875=4.69%.\boxed{(A\prime-A)/A=3/64=.046875=4.69\%}.

Physical check

Ionization changes the electron count but neither Z nor A. Isotopes share a proton number while differing in neutron number.